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seropon [69]
2 years ago
9

How many molecules does 85.0 g HCl contain?

Chemistry
2 answers:
spayn [35]2 years ago
5 0
Moles = grams/molar mass
Moles = 85/(1+35.5)
Moles = 2.33

Multiply by agrovados number (6.022 * 10^23) to get

1.401917808219x10^24 molecules

C is the answer

Hope this helped :)

Ratling [72]2 years ago
4 0

Answer: C. 1.40×10^24

Explanation:

To do this, we must convert this from grams to moles, then from moles to molecules. For the first step, you will need to find the molar mass of HCl on the periodic table, which is 36.461gHCl.

85.0gHCl*\frac{1molHCl}{36.461gHCl} =2.33molHCl

Now that we have the moles, we must convert that to molecules by using Avogadro's number.

2.33molHCl*\frac{6.022*10^{24} }{1molHCl} =1.40*10^{24}

Now we have our answer. The best answer choice here is C. 1.40×10²⁴.

I hope this helps! Pls mark brainliest!! :)

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When NAD becomes NADH, it is being reduced and gaining chemical energy.

Nicotinamide adenine dinucleotide (NAD), a coenzyme, can exist in two forms, NAD⁺ (oxidized) and NADH (reduced form).

Electrons and protons released in catabolism reactions are attached to NAD⁺. The conversion of NAD⁺ to NADH is important reaction for production of ATP during the cellular respiration.

Reduction is lowering oxidation number because element, ion or compound gain electrons.

Chemical equation for reaction of reduction of NAD⁺ (see picture below):

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8 0
2 years ago
A student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 16.428 g. After a second heatin
jolli1 [7]

Answer:

12.371 g

Explanation:

Given :

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{evaporating\ dish}+m_{First\ heated\ sample}=16.428\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

Mass of salt hydrate:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Hydrate\ sample}=25.637\ g

m_{Hydrate\ sample}=25.637-m_{evaporating\ dish}\ g=25.637-1.135\ g=24.502\ g

Mass of salt anhydrous:

m_{evaporating\ dish}=1.135\ g

m_{evaporating\ dish}+m_{Second\ heated\ sample}=13.266\ g

m_{Second\ heated\ sample}=m_{salt\ anhydrous}=13.266-m_{evaporating\ dish}\ g=13.266-1.135\ g=12.131\ g

Mass of water:

m_{water}=m_{Hydrate\ sample}-m_{salt\ anhydrous}=24.502-12.131\ g=12.371\ g

m_{water}=12.371\ g

4 0
4 years ago
What is the oxidation number for CO2
anzhelika [568]

Answer:

+4

Explanation:

The oxidation number of C in carbon dioxide (CO2) is (rules 1 & 2): 0 + (2 x 2) = +4 [Check (rule 3): +4 + 2(-2) = 0] The oxidation number of C in methane (CH4) is (rules 1 & 2): 0 – (4 x1) = -4 [Check (rule 3): -4 + 4(-1) = 0].

7 0
3 years ago
(iii) Give two reasons why the electrolyte contains cryolite​
V125BC [204]

Answer:

The mixture of cryolite and aluminum oxide has a lower melting point than pure aluminum oxide. This means a lower amount of energy is required to establish effective conditions for electrolysis and thus makes it more cost effective.

Explanation:

3 0
3 years ago
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid at 0°C?
Marrrta [24]
Energy released from changing the phase of a substance from the liquid phase to solid phase can be calculated by using the specific latent heat of fusion. The heat of fusion of water at 0 degrees Celsius is 334 J/g. Calculation are as follows:
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</span><span>Energy = 1670 J</span>
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3 years ago
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