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lyudmila [28]
4 years ago
9

Carbon dioxide is a common gas produced in burning describe a test for carbon dioxide gas​

Chemistry
1 answer:
TEA [102]4 years ago
8 0

Answer:

burning gasoline

Explanation:

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A 0.25 M solution of NaCl must be diluted into a 250 mL solution (0.08 M). What volume should be taken from the original solutio
mihalych1998 [28]

Answer:

80ml

Explanation:

you have your initial concentration to be 0.25 mole on your final volume to be 250 ml and your final concentration to be 0.8 0.08 molar you don't have your initial volume sotify your initial volume you use the expression see 1 * 21 equals see two times between you make when when the subject then 1 equals to 2 x 2/3 one you know substitute your values into it to get being one that's your original volume to be at the latest or 80 ml

7 0
4 years ago
The reaction of 9.50 g of carbon with Excess O2 Yield 12.8 of CO2. What is the percent yield of this reaction?
Anna [14]

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

5 0
3 years ago
For each molecule below draw the structural formula of the molecule
torisob [31]
I think you forgot to post a picture
5 0
4 years ago
A scientist prepared an aqueous solution of a 0.45 M weak acid. The pH of the solution was 2.72. What is the percentage ionizati
aleksandr82 [10.1K]

Answer:

0.42%

Explanation:

<em>∵ pH = - log[H⁺].</em>

2.72 = - log[H⁺]

∴ [H⁺] = 1.905 x 10⁻³.

<em>∵ [H⁺] = √Ka.C</em>

∴ [H⁺]² = Ka.C

∴ ka = [H⁺]²/C = (1.905 x 10⁻³)²/(0.45) = 8.068 x 10⁻⁶.

<em>∵ Ka = α²C.</em>

Where, α is the degree of dissociation.

<em>∴ α = √(Ka/C) </em>= √(8.065 x 10⁻⁶/0.45) = <em>4.234 x 10⁻³.</em>

<em>∴ percentage ionization of the acid = α x 100</em> = (4.233 x 10⁻³)(100) = <em>0.4233% ≅ 0.42%.</em>

4 0
3 years ago
Read 2 more answers
45. What are the products of a neutralization reaction? (2 points)<br> DOWE
MAVERICK [17]

Answer:

Salt and water are the products of neutralization reaction

Example:

NaOH + HCl➡NaCl+H2O

8 0
4 years ago
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