Answer:
Height of flagpole = 571 ft
Step-by-step explanation:
Given:
Angle of elevation to the top of the flagpole is 55° .
Distance from the eyes to the base of flagpole = 400 ft.
To find the height of the flagpole.
Solution:
We can draw the situation as a right triangle as shown below.
In triangle ABC.
∠C= 55°
To find the length AB (height of the flagpole).
Applying trigonometric ratio :
Plugging in values.
Multiplying both sides by 400.
∴ 
Height of flagpole = 571 ft
Answer:
= - 6 x + 20 y - 16
Step-by-step explanation:
step one . multiply the parenthesis by -2
step two . multiply whats left
step three . DONE
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Y = height
x = distance from tower
tan(19.9) = y/x
tan(21.8) = y/(x-50) ( x is 50 feet closer so subtract 50 from x)
find the tan of the angles:
tan19.9 = 0.362
tan21.8 = 0.400
replace those values in the equations:
0.362 = y /x
0.400 = y / (x-50)
rewrite to solve for height:
0.362x = y
0.400(x-50) = y distribute the 0.400 and rewrite as 0.400x-20 =y
now solve:
0.362x = 0.400x-20
add 20 to each side:
0.362x +20 = 0.400x
subtract 0.362x from each side:
20 = 0.038x
divide both sides by 0.038
x = 20 / 0.038 = 526.3 feet
now that x is known replace x in the original equation and solve for y:
tan19.9 = y /x
0.362 = y / 526.3
y = 0.362 x 526.3
y = 190.5
the height of the tower is 190.5 feet
9a^2 -6ab+ 12ac -8bc
This expression cannot be factorized because its terms don't have at least a common factor~
