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const2013 [10]
3 years ago
14

Which generally occurs as temperature increases?

Chemistry
1 answer:
NikAS [45]3 years ago
8 0

Answer:

Hello, Your answer will be B) Solubility Increases.

Explanation:

Why The Answer is B, Because solubility increases with temperature. The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions. Hope That Helps!

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When NaCl dissolves in water
slava [35]
The sodium ion becomes hydrated. when sodium chloride dissolves in water, the sodium and chloride ions and the polar water molecules are strongly attracted to one another by ion-dipole interactions
6 0
3 years ago
If a gas has a volume of 350 mL at 780 mm Hg, what pressure will be needed to cause its volume
makkiz [27]

The required pressure of the gas is 546 mmHg.

<h3>What is the relation between volume and pressure?</h3>

Relation between the volume and pressure of gas is explained through the ideal gas equation PV = nRT, and for the question required equation is:

P₁V₁ = P₂V₂, where

P₁ & V₁ are the initial pressure and volume.

P₂ & V₂ are the final pressure and volume.

On putting values from the question to the equation, we get

P₂ = (780)(350) / (500) =

P₂ = 546 mmHg

Hence required pressure is 546 mmHg.

To know more about ideal gas equation, visit the below link:

brainly.com/question/24236411

#SPJ1

5 0
2 years ago
I need help.... I wasn't taught this, I was sick and she doesn't do anything to help me!
Ghella [55]

Answer:

The answer to your question is:

52.- E, A, D, B, C, F

53.- D, B, F, C, A, E

Explanation:

52.- Gamma, Ultraviolet, Blue, Red, Infrared, Microwaves

53.- X-ray, ultraviolet, green, orange, infrared, radio

4 0
3 years ago
Ammonia, NH3 is a common base with Kb of 1.8 X 10-5. For a solution of 0.150 M NH3:
Vesnalui [34]

The concentrations : 0.15 M

pH=11.21

<h3>Further explanation</h3>

The ionization of ammonia in water :

NH₃+H₂O⇒NH₄OH

NH₃+H₂O⇒NH₄⁺ + OH⁻

The concentrations of all species present in the solution = 0.15 M

Kb=1.8 x 10⁻⁵

M=0.15

\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}

\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21

8 0
3 years ago
What is the unit of measure when using a beaker
yulyashka [42]
When Use a beaker you measure in ml.
5 0
3 years ago
Read 2 more answers
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