and
do not have the same geometry. Both
and
has two side atoms but the number of bond pair and lone pair are different.
has only two bond pair with no lone pair while
has two bond pair with two lone pair.
Further Explanation:
Lewis structure of
:
The total number of valence electrons of
is calculated as,
Total valence electrons = [(1) (Valence electrons of C) + (2) (Valence electrons of O)]
![\begin{aligned}{\text{Total valence electrons}}\left({{\text{TVE}}}\right)&=\left[ {\left( {\text{1}} \right)\left({\text{4}}\right)+\left( {\text{2}}\right)\left({\text{6}}\right)}\right]\\ &=16\\\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%7B%5Ctext%7BTotal%20valence%20electrons%7D%7D%5Cleft%28%7B%7B%5Ctext%7BTVE%7D%7D%7D%5Cright%29%26%3D%5Cleft%5B%20%7B%5Cleft%28%20%7B%5Ctext%7B1%7D%7D%20%5Cright%29%5Cleft%28%7B%5Ctext%7B4%7D%7D%5Cright%29%2B%5Cleft%28%20%7B%5Ctext%7B2%7D%7D%5Cright%29%5Cleft%28%7B%5Ctext%7B6%7D%7D%5Cright%29%7D%5Cright%5D%5C%5C%20%26%3D16%5C%5C%5Cend%7Baligned%7D)
In
, the total number of valence electrons is 16. Here, carbon atoms form two double bond with the two oxygen atoms, therefore, 8 pair of electrons are used in the formation of two double bonds with the oxygen atoms. Rest 8 electrons are distributed to complete the octet of oxygen atoms.
According to the Lewis structure of
central atom carbon has only two bond pair with no lone pair thus,
has
electron group arrangement. Therefore,
has linear geometry and linear shape.
Lewis structure of
:
The total number of valence electrons of
is calculated as,
Total valence electrons = [(1) (Valence electrons of O) + (2) (Valence electrons of H)]
![\begin{aligned}{\text{Total valence electrons}}\left({{\text{TVE}}} \right)&=\left[{\left( {\text{1}}\right)\left({\text{6}}\right)+\left({\text{2}}\right)\left({\text{1}}\right)}\right]\\&=8\\\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%7B%5Ctext%7BTotal%20valence%20electrons%7D%7D%5Cleft%28%7B%7B%5Ctext%7BTVE%7D%7D%7D%20%5Cright%29%26%3D%5Cleft%5B%7B%5Cleft%28%20%7B%5Ctext%7B1%7D%7D%5Cright%29%5Cleft%28%7B%5Ctext%7B6%7D%7D%5Cright%29%2B%5Cleft%28%7B%5Ctext%7B2%7D%7D%5Cright%29%5Cleft%28%7B%5Ctext%7B1%7D%7D%5Cright%29%7D%5Cright%5D%5C%5C%26%3D8%5C%5C%5Cend%7Baligned%7D)
In
, the total number of valence electrons is 8. Here, oxygen forms single bond with the hydrogen atom, therefore, 2 pair of electrons are used in the formation of two single bonds with hydrogen atom. Rest 4 electrons are used to complete the octet of oxygen atom.
According to the Lewis structure of
central atom oxygen has two bond pair with two lone pair and
has
electron group arrangement. Therefore,
has a tetrahedral geometry and has bent shape.
Therefore,
and
do not have the same geometry.
Learn more:
1. Molecular shape around each of the central atoms in the amino acid glycine: brainly.com/question/4341225
2. How many molecules will be present on completion of reaction?: brainly.com/question/4414828
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Molecular structure and chemical bonding
Keywords: Shape, molecular shape, tetrahedral, bent, bent shape, lewis structure, valence, valence electron, H2O, CO2, lone pair, bond pair, charge, geometry, linear.