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zvonat [6]
3 years ago
14

Rays traveling parallel to the principle axis of a concave mirror will reflect out through the mirrors focus?

Physics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

True

Explanation:

When a ray travelling parallel to the principle axis of a concave mirror then the light ray reflect out through the mirrors and passing through the focus.

When a light ray travelling through focus of a concave mirror then after reflection the light ray reflect out through the mirror and  go parallel to principle axis.

Therefore, rays travelling parallel to the principle axis of a  concave mirror will reflect out through the mirrors focus.

It is true.

kompoz [17]3 years ago
7 0

Answer:

true

Explanation:

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I drop an egg from a certain distance and it takes 3.74 seconds to reach the ground. How high up was the egg?
OverLord2011 [107]

Answer:

68.5 meters

Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3.74 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0) (3.74) + ½ (9.8) (3.74)²

Δy = 68.5

The egg fell 68.5 meters.

7 0
3 years ago
Andrew is riding his bike is riding in a circle that has a radius of 10 m. He keeps
Dmitrij [34]

The acceleration that Andrew experience  during his ride is 3.6m/s²

The formula for calculating centripetal acceleration is expressed as:

a = v²/r

v is the speed

r is the radius

Given the following expression

v = 6m/s

r = 10m

Substitute the given parameters into the formula

a = 6²/10

a = 36/10

a = 3.6m/s²

Hence the acceleration that Andrew experience  during his ride is 3.6m/s²

Learn more here: brainly.com/question/1268866

8 0
2 years ago
Your electric drill rotates initially at 5.21 rad/s. You slide the speed control and cause the drill to undergo constant angular
RUDIKE [14]

Answer:

The drill's angular displacement during that time interval is 24.17 rad.

Explanation:

Given;

initial angular velocity of the electric drill, \omega _i = 5.21 rad/s

angular acceleration of the electric drill, α = 0.311 rad/s²

time of motion of the electric drill, t = 4.13 s

The angular displacement of the electric drill at the given time interval is calculated as;

\theta = \omega _i t \ + \ \frac{1}{2}\alpha t^2\\\\\theta = (5.21 \ \times \ 4.13) \ + \ \frac{1}{2}(0.311)(4.13)^2\\\\\theta = (21.5173 ) \ + \ (2.6524)\\\\\theta =24.17 \ rad

Therefore, the drill's angular displacement during that time interval is 24.17 rad.

6 0
3 years ago
If a 4.0Ω resistor, a 6.0Ω resistor, and an 8.0Ω resistor are connected in parallel across a 12 volt battery, what is the total
allsm [11]

Answer:

Explanation:

6.7 amps

7 0
2 years ago
A uniform linear charge of 2.0 nC/m is distributed along the x axis from x = 0 to x = 3 m. What is the x component of the electr
balu736 [363]

Answer:

The x component of the electric field at y=2m is E_{x}=17.97\frac{N}{C}

Explanation:

For a linear charge, using <u>Gauss Law</u>, we get that the <em>Electric field (radial) has the following form</em>

E=\frac{\lambda}{2\pi\epsilon_{0}r}

<em>where λ is the charge for longitud unit given in the problem, r is replaced by the y coordinate, and there are two known more data</em>. So

E=\frac{2*10x^{-9}}{2*2\pi\epsilon_{0}}=17.97\frac{N}{C}

is the x component of the Electric field at y=2m on the y axis, which is what we wanted to know.

4 0
3 years ago
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