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PtichkaEL [24]
3 years ago
11

Given: SP = PT = ST = 2.6 MO⊥ (SPT) m∠MPO = 70º Find: Volume

Mathematics
1 answer:
ohaa [14]3 years ago
4 0

Answer:

Step-by-step explanation:

Volume = 1/3(area of triangular base)height

To find the triangular base we would use heron formula Area = square root (s-a)(s-b)(s-c)

S = (a+b+c)/2 = 2.6 + 2.6 + 2.6 )/2

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Can someone help me please!!!
Morgarella [4.7K]

Answer: P=1200x+35000

Step-by-step explanation:

Given: A town's population has been growing linearly. In 2003, the population was 35000, and the population has been growing by 1200 (constant rate of change) people each year.

The equation of a line is given by :-

y=mx+c, where m is the slope ( constant rate of change) and c is the initial value of the function.

From the given statement , we have the equation for the population x years after 2003 :-

P=1200x+35000

6 0
3 years ago
BRAINLIEST <br> please leave a small explanation:)
Contact [7]

Answer:

I say D cuz if u look at it, it's a pretty wide enough angle to be at least 47°

4 0
3 years ago
Read 2 more answers
Factor 6 z^3/3 + 1 z^1/3
balandron [24]

Use Rule of One: x^1 = x

6 × x^3 + 1 × z/3

Simplify 6 × z^3/3 to 2z^3

2z^3 + 1 × z/3

Simplify 1 × z/3 to z/3

<u>= 2z^3 + z/3</u>

7 0
3 years ago
Who knows how to do this ughhh I need help!
suter [353]

Answer:

\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}

8 0
3 years ago
Solve for x. round to the nearest hundredth if necessary.
iris [78.8K]

Answer: x=11.47

Step-by-step explanation:

Given the angle of 55 degrees, you know that the adjacent side is "x" and the length of the hypotenuse is 20.

Therefore, you need to remember the following identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Then, knowing that:

\alpha=55\°\\adjacent=x\\hypotenuse=20

 You need to substitute these values intocos\alpha=\frac{adjacent}{hypotenuse}:

 cos(55\°)=\frac{x}{20}

Now, you can solve for "x":

20*cos(55\°)=x\\x=11.471

Rounded to the nearest hundreth:

x=11.47

6 0
3 years ago
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