Answer:
1. Potassium, K.
2. Calcium, Ca.
3. Gallium, Ga.
4. Carbon, C.
5. Bromine, Br.
6. Barium, Ba.
7. Silicon, Si.
8. Gold, Au.
Explanation:
Atomic radius can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
Additionally, the unit of measurement of the atomic radius of chemical elements is picometers (1 pm = 10 - 12 m).
1. Li or K: the atomic radius of lithium is 167 pm while that of potassium is 243 pm.
2. Ca or Ni: the atomic radius of calcium is 194 pm while that of nickel is 149 pm.
3. Ga or B: the atomic radius of gallium is 136 pm while that of boron is 87 pm.
4. O or C: the atomic radius of oxygen is 48 pm while that of carbon is 67 pm.
5. Cl or Br: the atomic radius of chlorine is 79 pm while that of bromine is 94 pm.
6. Be or Ba: the atomic radius of berryllium is 112 pm while that of barium is 253 pm.
7. Si or S: the atomic radius of silicon is 111 pm while that of sulphur is 88 pm.
8. Fe or Au: the atomic radius of iron is 156 pm while that of gold is 174 pm.
Answer: A butterfly population includes both green and yellow butterflies, and a predator sees yellow more easily than it does green" would lead to evolution since the green ones would live on.
Explanation:
Answer: Proteins are known as biomolecules and biomolecules are made of the elements Carbon, Hydrogen, Nitrogen, and Oxygen and the monomers of proteins are known as amino acids.
Answer:
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Explanation:
ehehrhrhrhrhrhrhr. dvdhdhrhrhehehr f fbdhehrgdgdhehd dbdh
Answer:
5. +5
6. +7
Explanation:
The oxidation state can be obtained as follow:
5. Oxidation state of oxygen, O = –2
Oxidation state of phosphorus, P =?
P3O10 = –5
3P + 10O = –5
3P + (10 x –2) = –5
3P – 20 = –5
Collect like terms
3P = –5 + 20
3P = 15
Divide both side by 3
P = 15/3
P = +5
Therefore, the oxidation state of P in P3O10^5- is +5
6. Oxidation state of oxygen, O = –2
Oxidation state of manganese, Mn =.?
Mn2O7 = 0
2Mn + 7O = 0
2Mn + (7 x –2) = 0
2Mn – 14 = 0
Collect like terms
2Mn = 14
Divide both side by 2
Mn = 14/2
Mn = +7
Therefore, the oxidation state of Mn in Mn2O7 is +7
