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4 years ago

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An Alaskan rescue plane traveling 37 m/s drops a package of emergency rations from a height of 134 m to a stranded party of expl

orers. The acceleration of gravity is 9.8 m/s^2. Where does the package strike the ground relative to the point directly below where it was released?

1 answer:

photoshop1234 [79]4 years ago

6 0

vf = - 46 m/s since up is positive

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What is the sum of a systems potential and kinetic energy is equal to?

vekshin1

Answer:

Explanation:

TE = KE + PE which is total energy available to a system is equal to its potential energy plus its kinetic energy, and that total energy will remain throughout the entire "trip", whatever it might be. So a is your answer.

8 0

3 years ago

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

muminat

Answer:

18.375

Explanation:

Mean = total of measured values / no of elements of sample

Total = .15 + .89 +1.11+1.46 +2.78 + 3.12 + 4.30 + 4.59 + 4.92 + 6.42 + 7.20+8.04+8.21+12.13+31.86+32.53+33.82+36.60+ 72.99

= 273.03

Mean = 273 .03 / 19

= 14.37

( .15 - 14.37 )² +( 0.89 - 14.37 )²+( 1.11- 14.37 )²+( 1.46 - 14.37 )²+( 2.78 - 14.37 )²+( 3.12 - 14.37 )²+( 4.30 - 14.37 )²+( 4.59 - 14.37 )²+( 4.92 - 14.37 )²+( 6.42 - 14.37 )²+( 7.20 - 14.37 )²+( 8.04 - 14.37 )²+( 8.21 - 14.37 )²+( 12.13 - 14.37 )²+( 31.86 - 14.37 )²+( 32.53 - 14.37 )²+( 33.82 - 14.37 )²+( 36.60 - 14.37 )²+( 72.99 - 14.37 )²

= 202.20 +181.71+ 175.82 + 166.66+ 134.32 + 126.56 + 101.40 +95.64 + 89.30 +63.20 +51.40 +40.06 +37.94+5.01 +305.90 +329.78 +378.30 +494.17 +3436.30

=6415.67

Standard deviation =

$\sqrt{\frac{6415.67}{19} }$

= 18.375

5 0

3 years ago

Which of the following statements is true about isotopes? Question options: The number of protons always equals the number of ne

arlik [135]

The number of protons always equals the number of neutrons in all isotopes: false

Different isotopes for the same element always have the same number of protons: True

The number of protons never equals the number of neutrons in an isotope: False (example: He)

Different isotopes for the same element will always have the same numbers of neutrons: false

5 0

4 years ago

Read 2 more answers

The molar enthalpy of fusion for water is 6.008 kj/mol. what quantity of energy is released when 253g of liquid water freezes? (

e-lub [12.9K]

During freezing, energy is released by the mass of water without change in temperature. Such energy will also be required if the same mass of water has to be melted.

Then,

Number of moles = mass/molar mass = 253/18.02 =14.04 moles

Energy released = moles*molar enthalpy of fusion = 14.04*6.008 = 84.35 kJ

6 0

3 years ago

You are observing a spacecraft moving in a circular orbit of radius 100,000 km around a distant planet. You happen to be located

Natalija [7]

To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:

$v_{o} = c (\frac{\lambda_{max}-\bar{\lambda}}{\bar{\lambda}}})$

Here,

$v_{o} =$ Orbital Velocity

$\lambda_{max} =$ Maximal Wavelength

$\bar{\lambda}} =$ Average Wavelength

c = Speed of light

Replacing with our values we have that,

$v_{o} = (3*10^5) (\frac{3.00036-3}{3})$

<em>Note that the average signal is 3.000000m</em>

$v_o = 36 km/s$

Now using the definition about centripetal acceleration we have,

$a_c = \frac{v^2}{r}$

Here,

v = Orbit Velocity

r = Radius of Orbit

Replacing with our values,

$a = \frac{(36km/s)^2}{100000km}$

$a= 0.01296km/s^2$

$a = 12.96m/s^2$

Applying Newton's equation for acceleration due to gravity,

$a =\frac{GM}{r^2}$

Here,

G = Universal gravitational constant

M = Mass of the planet

r = Orbit

The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,

$M = \frac{ar^2}{G}$

$M = \frac{(12.96)(100000000)^2}{ 6.67*10^{-11}}$

$M = 1.943028*10^{27}kg$

Therefore the mass of the planet is $1.943028*10^{27}kg$

7 0

3 years ago