14 you have to multiply the 7 by the 2
Answer:
e = 10 V
Explanation:
given,
number of the coaxial loops = 10
Cross sectional area = 0.5 m²
magnitude of magnetic field =
B = 3 T + (2 T/s)*t.
B = ( 3+ 2 t ) T
induced potential difference = ?
At time = 2 s
we know,
induced emf
∅ = B . A
e = -10 V
magnitude of induced emf
|e| = |-10 V|
e = 10 V
the induced potential difference in the loop = e = 10 V
The relation between the angle of incidence and the angle of refraction is known as Snell's Law. Since the light travels with different speed in different media, the direction of the ray of light will change when it crosses the boundary between the two media
Answer:
F = 20.07 μN
Explanation:
given,
intensity of sunlight = 667 W/m²
area of surface = 9.03 m²
speed of light = 3 x 10⁸ m/s
force = ?
we know
force =
force =
F = 20.07 x 10⁻⁶ N
F = 20.07 μN
Let the cannonball be thrown at a height of h above ground.
Then the potential energy of the ball is
V = m*g*h
where
m = the mass of the ball
g = 9.8 m/s²
Also, the kinetic energy of the ball is
K = (1/2)mu²
where
u = 5 m/s, the vertical launch velocity.
Ignore wind resistance.
Because the total energy is preserved, the total energy (n the form of only kinetic energy) when the ball strikes the ground is
(1/2)mV²
where V = vertical velocity when the ball strikes the ground.
Expressions for both the initial and final energy are equal regardless of whether the ball s thrown downward or upward.
Therefore there is no difference in the landing speed.
Answer: There is no difference.
