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AlekseyPX
3 years ago
11

Show how you got from 135 to to 175 counting by fives

Mathematics
2 answers:
Rudiy273 years ago
6 0
All you do is just count by fives...it's pretty easy. 135, 140, 145, 150, 155, 160, 165, 170, 175, and so on
Rus_ich [418]3 years ago
4 0
135, 140, 145, 150, 155, 160, 165, 170, 175.
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What does geometric progression mean?
damaskus [11]

Step-by-step explanation:

\large\tt\underline\blue{a} \underline\pink{n} \underline\green{s} \underline\red{w}\underline \purple{e}  \underline\orange{r}

A geometric progression is a sequence in which any element after the first is obtained by multiplying the preceding element by a constant called the common ratio which is denoted by r.

7 0
2 years ago
Tony is trying to calculate how much ice cream he will need to order for his ice cream shop by figuring out the volume of ice cr
vredina [299]
Vsphere=(4/3)pi times r^3

r=radius
given that r=2

v=(4/3)pi2^3
v=(4/3)pi8
v=32/3pi cubic inches
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5 0
3 years ago
Please help! I do not know how to find the unknown variables using the Pythagorean theorem. Any help will be greatly appreciated
Aliun [14]

Answer:

pythagorean theorem=a squared + b squared =c squared

where c is the hypotenus(the longest part)

Step-by-step explanation:

16 squared = 8 squared +....

16 ×16=256=8×8=64 + y

256_64=192

sq. root of 192=13.85

y=180_90=90

90÷2=45

y=45

z=45

x=13.85cm

hope you understand

3 0
3 years ago
Consider a parent population with mean 75 and a standard deviation 7. The population doesn’t appear to have extreme skewness or
Aleks04 [339]

Answer:

a) \bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

b) Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

c) P(\bar X \leq 77)=P(Z

d) See figure attached

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variable of interest. We know from the problem that the distribution for the random variable X is given by:

E(X) = 75

sd(X) = 7

We take a sample of n=40 . That represent the sample size

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=375, \sigma={\bar X}=\frac{7}{\sqrt{40}}=1.107)

Part b

Since the sample size is large enough n>30 and the original distribution for the random variable X  doesn’t appear to have extreme skewness or outliers, the distribution for the sample mean would be bell shaped and symmetrical.

Part c

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X \leq 77)=P(Z

We can us the following excel code: "=NORM.DIST(1.807,0,1,TRUE)"

Part d

See the figure attached.

8 0
3 years ago
Need help asap with b and c!!! plz help for a cookie :)
Debora [2.8K]
You can think of this question like the photo attached above.

Hi!

I think for b, the answer would be:

You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.

I think for c, the answer would be:

You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.

Hope this helps! Best of luck!



4 0
3 years ago
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