Answer:
The answer is
<h2>40.0 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass = 420 g
density = 10.5 g/cm³
The volume is

We have the final answer as
<h3>40.0 mL</h3>
Hope this helps you
Redox reaction has a great economic impact. many product that we use in our daily lives are made using redox reaction. some of which are electroplating, that we use in our watches. and redox reaction also caused the rusting of irons, so buildings will rust and become brittle
There is 12 inches in 1 foot.
Divide 16 with 12 to get feet
16/12 = ~1.33 (rounded)
1.33 is your answer
hope this helps
Answer:
The time decreases steadily
Explanation:
We know that the rate of chemical reaction is defined as how fast or slow a chemical reaction proceeds. Hence a chemical reaction is said to proceed at a faster rate if it takes a lesser time for the reaction to get to completion.
There are certain factors that affects the rate of reaction, prominent among them is the concentration of reactants. Concentration simply means the amount of substance in a system.
Taking a look at the table given in the question, we will realize that the volume of HCl remained constant, the volume of thiosulphate increased steadily while the volume of water decreased steadily. Remember that concentration increases when less water is added to the system. This implies that the reactant concentration increases steadily. Hence, according to the collision theory, particles collide more frequently and the rate of reaction increases.
As the rate of reaction increases, it now takes a lesser time for the reaction to get to completion (indicated by the disappearance of the cross). Hence as we move down the table, it takes lesser and lesser time for the cross to disappear. This means that the column for time will decrease steadily.
Answer:
please brainlist answer
Explanation:
The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.