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ohaa [14]
4 years ago
12

A speeding car collides with an unlucky bug flying across the road. Which explains why the impact doesn’t equally damage the car

and the bug?
Physics
1 answer:
velikii [3]4 years ago
8 0
The bug was a lot smaller than the car, that's for sure. The car is bigger and sturdier, while the bug is smaller and frail. The bug is so frail, that rather that putting a dent in the car, it splatters all over the car. The bug is very damaged (obviously), while the car just needs a good wash.
You might be interested in
Which statement about the accuracy and precision of measuring tools is
adelina 88 [10]

The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

Learn more about accuracy.

brainly.com/question/13099041

#SPJ1

4 0
2 years ago
By how much will the velocity of a vehicle change if it accelerates at 10 m/s/s for a period of 10 seconds​
pishuonlain [190]

Answer:

Explanation:

we know that the time rate of change of velocity is called acceleration mathmetically;

a=Δv/Δt

Δv=a*Δt

a=10 m/s²

t=10 sec

Δv=10*10=100 m/s

7 0
4 years ago
An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi
shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = a^{2}

Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
4 years ago
Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni
sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

F\propto q_1q_2

When each of the spheres has lost half its initial charge, we have:

q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}

So, the new electrostatic force is:

F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F

5 0
4 years ago
You and your friend Peter are putting new shingles on a roof pitched at 21∘. You're sitting on the very top of the roof when Pet
Marat540 [252]

Answer:

3.69 m/s

Explanation:

Forces :

mgsin Θ - mumgcosΘ = ma  

g x sinΘ  - mu x g x cosΘ  = a

9.8 x sin 21 - 0.53 x 9.8 x cos 21 = a

a = -1.337 m/s²

so you have final velocity = 0 m/s

initial velocity = ? m/s

Given d = 5.1 m

By kinematics

vf² = vo² + 2ad

0 = vo² + 2 x -1.337*5.1

vo = 3.69 m/s

8 0
4 years ago
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