I’m pretty sure it’s speed=distance/time
The distance of the ship from the shore is 1020m
<u>Explanation:</u>
Given:
Speed, s = 340 m/s
Time, t = 10s
Distance, x = ?
The sound is going to have to go to shore, then come back.
The total round-trip distance is
D = speed X time
D = (340 m/s) * (6.0 s)
D = 2,040 m
But as previously stated, the sound had to get there, then come back. So the actual ship-to-shore distance is only half that.
x = D/2
Therefore, the distance of the ship from the shore is 1020m
Answer:
max height = 473.68 m
velocity hit mars = 60 m/s
Explanation:
Maximum height can be found by finding the 1st derivative of s(t) and equate it to zero.
s'(t) = ds/dt = 60 - 3.8t
s't() = 0
60 - 3.8t = 0
3.8t = 60
t = 60/3.8 = 15.79
subs t = 15.79 to s(t)
s(15.79) = 60(15.79) - 1.9(15.79)^2 = 473.68 m
b) The arrow will hit mars after it went up to the maximum height and travelled back downward due to gravity
Assuming the gravity constant, the velocity when it hit the ground should be the same as it leaves the ground. To confirm that, we tested with the equation of motion.
Since there is no gravity given, let a downward as g
v^2 = u^2 + 2as
The arrow shot upward will comes back downward. Since gravity is always constant, the time it took back to reach the ground should be the same as it goes up to max height
so, t = 2*15.79 = 31.58 s
s = 0 since we are looking at the moment it touches back the ground
v^2 = u^2 +2as
v^2 = 60^2 + 2g(0)
v^2 = 60^2
v = 60 m/s
Entropy and the second Law of Thermodynamics
Dissolving salt into water lowers the temperature which the water freezes, or at which the ice melts
Hope I helped! (: