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Liono4ka [1.6K]
2 years ago
14

A(n) _____ wave best describes a wave whose direction of travel is perpendicular to the displacement of the medium.

Physics
2 answers:
rewona [7]2 years ago
8 0
A(n) Transverse wave best describes a wave whose direction of travel is perpendicular to the displacement of the medium.
FrozenT [24]2 years ago
4 0

Answer:

b

Explanation:

defenettly right

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How much power is used by a car engine if it does 48496 J of work in 4 min?
elena-14-01-66 [18.8K]

<em>Hope this will help u</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>✌</em><em>✌</em><em>✌</em>

8 0
3 years ago
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The moon orbits the earth at a distance of 3.85 x 10^8 m. Assume that this distance is between the centers of the earth and the
Inga [223]

Answer:

27.5 days

0.92 month

Explanation:

r = radius of the orbit of moon around the earth = 3.85\times10^{8} m

M = Mass of earth = 5.98\times10^{24} m

T = Time period of moon's motion

According to Kepler's third law, Time period is related to radius of orbit as

T^{2} = \frac{4\pi ^{2} r^{3}  }{GM}

inserting the values, we get

T^{2} = \frac{4(3.14)^{2} (3.85\times10^{8})^{3}  }{(6.67\times10^{-11})(5.98\times10^{24})}\\T = 2.3754\times10^{6} sec

we know that

1 day = 24 hours = 24 x 3600 sec = 86400 s

T = 2.3754\times10^{6} sec \frac{1 day}{86400 sec} \\T = 27.5 days

1 month = 30 days

T = 27.5 days \frac{1 month}{30 days} \\T = 0.92 month

6 0
3 years ago
The electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength
VARVARA [1.3K]
So the given value or the formula in getting the electric potential region of space is V=350/sqrt of x^2+y^2. So the given data is x and y is equals to 2.6 and 2.8. So in my calculation i came up with an answer of 91.6
8 0
3 years ago
a spring is stretched 20 cm by a 30.0 n force. determine the work done in stretching the spring from 0 to 40 cm?
Alekssandra [29.7K]

The work done when a spring is stretched from 0 to 40cm is 4J.

What is work done?

Work done is the magnitude of force multiplied by displacement of an object. It is also the amount of energy transferred to an object when work is done on that.

The work done on the spring to stretch to 40cm is,

F = kx

where F is force, k is force constant.

k = F / x = 10 N / 20 * 10^-2 m = 50 N/m

W = 0.5 * k * (x)^2

where W = work done, k = force constant.

W = 0.5 x 50 x (40 x 10^-2)^2 = 4 J.

Therefore, the work done on the spring when it is stretched to 40cm is 4J.

To learn more about work done click on the given link brainly.com/question/25573309

#SPJ4

3 0
1 year ago
Andrew is pushing this block to the right across on the floor. Which force in the free body diagram is pointing in the wrong dir
soldier1979 [14.2K]

Answer:

the normal force

Explanation:

The free-body diagram represents all the forces acting on an object. In this example, there are four forces acting on the box: an applied force, the friction (which always act opposite to the applied force), the weight of the box (which is always downward), and the normal force.

The normal force is the reaction force exerted by the surface on which the box is moving on the box, and this reaction force is always opposite to the force exerted by the box on the surface. Since the latter is downward, it means that the normal force must be upward, so in the diagram it is wrong.

8 0
3 years ago
Read 2 more answers
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