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3 years ago

D. What is one watt power? Calculate the power of

Physics

1 answer:

Tatiana [17]3 years ago

3 0

Answer:

437.5 watts.

Explanation:

One watt power (1-watt) is used to describe the situation of an electrical appliance where 1 joule of energy per seconds of time (1 J/s) is consumed or used.

According to the information in the question, a man can lift a load of 175N (Force) to a height of 25 m (distance) in 10 seconds (time).

Power = Workdone (J) ÷ time (s)

Workdone = Force (N) × distance (m)

Workdone = 175 × 25

Workdone (W) = 4375J

Power = W/t

P = 4375/10

P = 437.5 watts.

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Explanation:

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2 years ago

A science teacher who was teaching a unit on minerals modeled mineral formation for the class. She heated granular sugar and a v

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Answer:

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Explanation:

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3 years ago

Read 2 more answers

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Answer:

A.3.13x10^14 electrons

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3 years ago

he tune-up specifications of a car call for the spark plugs to be tightened to a torque of 47 N⋅m . You plan to tighten the plug

S_A_V [24]

Answer:

207.4 N

Explanation:

The torque $\tau$ on a body is

$\tau = r* F$ where r is the radius vector from the point of rotation to the point at which force F is applied.

The product of r and F is equal to the product of magnitude of r and F multiplied by the sine of angle between both vectors.

Therefore, torque is also given by

$\tau = rF\sin \theta$

Where $\theta$ is the angle between r and F.

Use the expression of torque.

Substitute L for r in the equation $\tau = rF\sin \theta$

$\tau = LF\sin \theta$

Where L is the length of the wrench.

Making F the subject

$F = \frac{\tau }{{L\sin \theta }}$

Force required to pull the wrench is given as,

$F = \frac{\tau }{{L\sin \theta }}$

Substitute $47{\rm{ N}} \cdot {\rm{m}}$ for $\tau$ , 25 cm for L, and 115o for $\theta$

$\begin{array}{c}\\F = \frac{{47{\rm{ N}} \cdot {\rm{m}}}}{{\left( {25{\rm{ cm}}} \right)\sin {{115}^{\rm{o}}}}}\left( {\frac{{1{\rm{ cm}}}}{{{{10}^{ - 2}}{\rm{ m}}}}} \right)\\\\ = 207.435{\rm{ N}}\\\\ \approx 207.4{\rm{ N}}\\\end{array}$

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3 years ago

A ball is thrown downward with an initial speed of 7 m / s. The ball's velocity after 3 seconds is m / s. (g = -9.8m / s²)

yan [13]

Answer:

-36.4 m/s

Explanation:

final velocity= initial velocity + acceleration x time

7 + (-9.8)(3)= -36.4 m/s

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3 years ago