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ratelena [41]
3 years ago
9

In February 1955, a paratrooper fell 362 m from an airplane without being able to open his chute but happened to land in snow, s

uffering only minor injuries. Assume that his speed at impact was 52 m/s (terminal speed), that his mass (including gear) was 86 kg, and that the force on him from the snow was at the survivable limit of 1.2 ✕ 105 N.What is the minimum depth of snow that would have stopped him safely?
Physics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

s = 0.9689 m

Explanation:

given,

Height of fall of paratroopers = 362 m

speed of impact = 52 m/s

mass of paratrooper = 86 Kg

From from snow on him = 1.2 ✕ 10⁵ N

now using formula

F = m a

a = F/m

a = \dfrac{1.2 \times 10^5}{86}

a =1395.35\ m/s^2

Using equation of motion

v² = u² + 2 a s

s =\dfrac{v^2}{2a}

s =\dfrac{52^2}{2\times 1395.35}

s = 0.9689 m

The minimum depth of snow that would have stooped him is  s = 0.9689 m

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krok68 [10]

Answer:

No. of revolutions before the car slides off is 2

Solution:

As per the question:

Mass of the car, m = 1500 kg

Diameter of the track, d = 50 m

Force, F = 525 N

Coefficient of static friction, \mu_{s} = 0.90

Now,

The acceleration in the tangential direction is given by:

F = ma_{T}

525 = 1500\times a_{T}

a_{T} = 0.35\ m/s^{2}

Here, the centripetal force is given by the friction force:

\frac{mv^{2}}{R} = \mu mg

Thus

v = \sqrt{\mu gR} = \sqrt{0.90\times 9.8\times 25} = 14.849\ m/s

Time taken by the car is given by:

v = v' + at

v' = initial velocity = 0

Thus

t = \frac{v}{a} = \frac{14.849}{0.35} = 42.426\ s

Total Distance covered, d is given by:

v^{2} = v'^{2} + 2ad

14.849^{2} = 0^{2} + 2\times 0.35d

d = 341.99 m

Distance covered in 1 revolution is the circumference of the circle, d' = 2\pi R

Now, the no. of revolutions is given by:

n = \frac{d}{d'} = \frac{314.99}{2\pi \times 25} = 2

5 0
3 years ago
Identify areas where winds are weak
tiny-mole [99]
Winds are weak in High Pressure area's
6 0
3 years ago
20. A car battery with a 12-V emf and an internal resistance of 0.050 Ω is being charged with a current of 60 A. Note that in th
topjm [15]

Answer:

Part a)

V = 15 Volts

Part b)

P = 180 Watt

Part c)

Rate = 720 Watt

Explanation:

Part a)

When battery is in charging then the potential difference of the terminals of cell is given by

\Delta V = EMF + iR

here we know that

EMF = 12 volts

i = 60 A

r = 0.050 ohm

now we have

\Delta V = 12 + (0.050)(60) = 15 Volts

Part b)

Rate of thermal energy dissipated is the energy which is dissipating across the resistor

so here we have

P = i^2 R

P = (60^2)(0.05)

P = 180 Watt

Part c)

Rate at which Energy stored inside the cell is the rate of electrical energy that is converted into the chemical energy

Rate = EMF \times i

Rate = (12)(60)

Rate = 720 Watt

6 0
3 years ago
What is the relationship between wavelength of light and the quantity of energy per photon?
slamgirl [31]

Answer:

The quantity of energy per photon is inversely proportional to the wavelength of the light.

Explanation:

Energy of light is given as

E = hf

where E = energy of the photons,

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If the number of photons = n

(E/n) = (h/n) f

Let (E/n) = E'

(h/n) = h'

But the frequency of light is related to wavelength through the relation

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λ = wavelength of light

f = (c/λ)

E' = h' f

Substituting for f

E' = h' (c/λ)

h' and c are both constants, h'×c = K

E' = (K/λ)

So, the quantity of energy per photon is inversely proportional to the wavelength of the light.

Hope this Helps!!!

3 0
3 years ago
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dangina [55]

Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

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<span>So the momentum = 1.5 kg(11.33 m/s) = 17 kg m/s</span>

8 0
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