Answer:
-4.37 * 10^(-18) J
Explanation:
Parameters given:
Charge of a proton, Qp = 1.6022 * 10^(-19) C
Charge of an electron, Qe = -1.6022 * 10^(-19) C
Distance between proton and electron, d = 0.529 × 10^(−10) m
The amount of work done is given as:
W = F * d
Where F = electrostatic force
d = distance between them
Electrostatic force is given as:
F = (k * Qp * Qe) / d²
F = (9 * 10^9 * 1.6022 * 10^(-19) * -1.6022 * 10^(-19)) / (0.529 × 10^(−10))²
F = -8.26 * 10^(-8) N
Work done will be:
W = -8.26 * 10^(-8) * 0.529 × 10^(−10)
W = -4.37 * 10^(-18) J
Answer:
The acceleration of the crate is 1 m/s²
Explanation:
It is given that,
Mass of the crate, m = 5 kg
Two forces applied on the crate i.e. one is 3.0 N to the north and the other is 4.0 N to the east. So, there resultant force is :
We need to find the acceleration of the crate. It is given by using the second law of motion as :
a = 1 m/s²
So, the acceleration of the crate is 1 m/s². Hence, this is the required solution.
Answer:
Trial 1: 2 Volts, 0 %
Trial 2: 2.8 Volts, 0%
Trial 3: 4 Volts, 0 %
Explanation:
Th experimental values are given in the table, while the theoretical value can be found by using Ohm/s Law:
V = IR
<u>TRIAL 1</u>:
V = IR
V = (0.1 A)(20 Ω)
<u>V = 2 volts</u>
% Difference = x 100%
% Difference = |(2 - 2)/2| x 100%
<u>% Difference = 0 %</u>
<u>TRIAL 2</u>:
V = IR
V = (0.14 A)(20 Ω)
<u>V = 2.8 volts</u>
% Difference = x 100%
% Difference = |(2.8 - 2.8)/2.8| x 100%
<u>% Difference = 0 %</u>
<u></u>
<u>TRIAL 3</u>:
V = IR
V = (0.2 A)(20 Ω)
<u>V = 4 volts</u>
% Difference = x 100%
% Difference = |(4 - 4)/4| x 100%
<u>% Difference = 0 %</u>
The fetus relies upon its mother as it develops. These are some of the things it needs:
<span>protection against knock and bumps, and temperature changes
oxygen for respiration
nutrients (food and water)
</span>
The developing fetus also needs its waste substances removing.
The fetus is protected by the uterus and the amniotic fluid, a liquid contained in a bag called the amnion.