It’s D bc Dt= 15x3 and it’s not that hard to solve
Answer:
< A = 148°
Step-by-step explanation:
<A = <B → 6x - 2° = 4x + 48° → 2x = 50° → x = 25°
<A = 6(25°) - 2° = 150° - 2° = 148°
Answer:
6x-108
Step-by-step explanation:
-3 · 2(7 · 2 - x + 4)
= ((−3)(2))((7)(2) +− x + 4)
= −84 + 6x − 24
= 6x − 108
The answer is 6x - 108
Each curve completes one loop over the interval

. Find the intersections of the curves within this interval.

The region of interest has an area given by the double integral

equivalent to the single integral

which evaluates to

.

common difference is
3.6 - 5.8 = -2.2
let T1 = 5.8
T2 = 3.6
assuming we are to find T2
T2 = T(2-1) -2.2
= T1 -22
= 5.8 -2.2
= 3.6