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eimsori [14]
4 years ago
7

28 19/100 in expanded form

Mathematics
1 answer:
djverab [1.8K]4 years ago
4 0
Answer: 20+8+0.1+0.09
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Please help! Just with Part B...
BARSIC [14]

Answer:

a) Number of calories burned in x hours of cycling 600x and Number of calories burned in y hours of Swimming is 400y.

b)The equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is 6x+4y=160.

Step-by-step explanation:

Given:

5 pounds of body fat = 16000 calories

Number of calories burn in 1 hour of cycling = 600

Number of calories burn in 1 hour of swimming = 400

Part a:

We need to find number of calories will Carol burn in x hours of cycling and number of calories will Carol burn in y hours of swimming.

Solution:

Now we know that;

1 hr of cycling = 600 calories burned

x hr of cycling = Number of calories burned in x hours of cycling.

By using Unitary method we get;

Number of calories burned in x hours of cycling = 600x

Also we know that;

1 hr of swimming= 400 calories burned

y hr of swimming = Number of calories burned in y hours of swimming.

By using Unitary method we get;

Number of calories burned in y hours of Swimming = 400y

Hence Number of calories burned in x hours of cycling 600x and Number of calories burned in y hours of Swimming is 400y

Part b:

We need to write equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds.

Solution:

Now given;

5 pounds = 16000 calories.

So we can say that;

Total number of calories to be burn is equal to sum of Number of calories burned in x hours of cycling  and Number of calories burned in y hours of Swimming.

framing in equation form we get;

600x+400y=16000

Now dividing both side by 100 we get;

\frac{600x}{100}+\frac{400y}{100}=\frac{16000}{100}\\\\6x+4y=160

Hence the equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is 6x+4y=160.

4 0
4 years ago
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