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ikadub [295]
3 years ago
8

What’s the slope of this chart? Explain how on a drawing if you want.

Mathematics
1 answer:
erik [133]3 years ago
4 0

Answer: the pic iznt working

Step-by-step explanation:

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What is 2 5/8+1 1/4?
vagabundo [1.1K]
<span>(2 5/8)+ (1 1/4) = </span>3.875
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3 years ago
WORTH 100 POINTS PLEASE HELP If you had a grade of 73.7% and scored a 54% on something that is worth 10% of your grade what is y
a_sh-v [17]

Answer:

5.4

Step-by-step explanation:

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3 years ago
Let R be the region in the first quadrant of the​ xy-plane bounded by the hyperbolas xyequals​1, xyequals9​, and the lines yequa
Tema [17]

Answer:

The area can be written as

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = 0.2274

And the value of it is approximately 1.8117

Step-by-step explanation:

x = u/v

y = uv

Lets analyze the lines bordering R replacing x and y by their respective expressions with u and v.

  • x*y = u/v * uv = u², therefore, x*y = 1 when u² = 1. Also x*y = 9 if and only if u² = 9
  • x=y only if u/v = uv, And that only holds if u = 0 or 1/v = v, and 1/v = v if and only if v² = 1. Similarly y = 4x if and only if 4u/v = uv if and only if v² = 4

Therefore, u² should range between 1 and 9 and v² ranges between 1 and 4. This means that u is between 1 and 3 and v is between 1 and 2 (we are not taking negative values).

Lets compute the partial derivates of x and y over u and v

x_u = 1/v

x_v = u*ln(v)

y_u = v

y_v = u

Therefore, the Jacobian matrix is

\left[\begin{array}{ccc}\frac{1}{v}&u \, ln(v)\\v&u\end{array}\right]

and its determinant is u/v - uv * ln(v) = u * (1/v - v ln(v))

In order to compute the integral, we can find primitives for u and (1/v-v ln(v)) (which can be separated in 1/v and -vln(v) ). For u it is u²/2. For 1/v it is ln(v), and for -vln(v) , we can solve it by using integration by parts:

\int -v \, ln(v) \, dv = - (\frac{v^2 \, ln(v)}{2} - \int \frac{v^2}{2v} \, dv) = \frac{v^2}{4} - \frac{v^2 \, ln(v)}{2}

Therefore,

\int\limits_1^2 \int\limits_1^3 u(\frac{1}{v} - v \, ln(v)) \, du \, dv = \int\limits_1^2 (\frac{1}{v} - v \, ln(v) ) (\frac{u^2}{2}\, |_{u=1}^{u=3}) \, dv= \\4* \int\limits_1^2 (\frac{1}{v} - v\,ln(v)) \, dv = 4*(ln(v) + \frac{v^2}{4} - \frac{v^2\,ln(v)}{2} \, |_{v=1}^{v=2}) = 0.2274

4 0
4 years ago
Please Help!!
kirill115 [55]

Answer:

x=10 x=5

Step-by-step explanation:

absalute value is the numarical distance away from 0

3 0
3 years ago
Estimate the area of the circle. use 3.14 3.14 or 22 7 227 for π π.
Aliun [14]

Answer:

615.44

Step-by-step explanation:

If the diameter is 28, that means the radius is 14.

The formula for the area of a circle is pi x radius to the power of 2. So, 14 to the power of 2 (or 14 x 14) equals 196. 196 x 3.14 (pi) = 615.44

4 0
2 years ago
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