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3 years ago

jamie is not sure a new medication will work because it has not had a large test group. Is jamie being creative?

Physics

2 answers:

gladu [14]3 years ago

8 0

No, he is being skeptical.

In the situation above Jamie doubts because the test was done with a small sample. He thinks the results are uncertain because it is needed a big sample to avoid mistakes and icrease the reliability of the study. So, this leads to scepticism, which means doubt about the truth of something, this is what Jamie does in the situation, this is why he is being skeptical.

elena-s [515]3 years ago

4 0

No, they're being skeptical.

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Why did Archimedes shout eureka what did he find out?

Natalka [10]

Answer:

I believe he shouted eureka after he stepped into a bath and noticed that the water rose. He then realized that the volume of water displaced must be equal to the volume of the part of his body he had submerged

Explanation:

8 0

3 years ago

(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.

Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

$BW = F_{c2}-F_{c1}$

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

$BW = (88-5)kHz$

$BW = 83kHz$

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

$f_0 = \sqrt{f_{c1}*f_{c2}}$

$f_0 = \sqrt{88*5}$

$f_0 = 20.97kHz$

7 0

3 years ago

Which electromagnetic wave enables us to see objects

Darina [25.2K]

Visible light because it enables us to see light and nklngdjofjjovjojiofhidhzfkbfjbjdbjbfueuishfihehfnih

6 0

3 years ago

A light ray is traveling in air with an index of refraction of unity and it is reflected at the boundary or a second medium with

user100 [1]

Answer:

Explained

Explanation:

Thickness coating= t

wavelength of light λ = 500 nm

2 t =(m+0.5)λ

Here m = 0

t= λ/4

= 500/4 nm

= 125 nm

= 125×10^(-9) m

5 0

4 years ago

A boat moves through the water with two forces acting on it. One is a 2.05 ✕ 103 N forward push by a motor, and the other is a 1

labwork [276]

Answer:

(a) a= 0.139 m/s²

(b) d= 4.45 m

Explanation:

a) We apply Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass (kg)

a : acceleration (m/s²)

Data

F₁= +2.05 * 10³ N : forward push by a motor

F₂= -1.87* 10³ N : resistive force due to the water.

m= 1300 kg

Calculation of the acceleration of the boat

We replace data in the formula (1):

∑F = m*a

F₁+F₂= m*a

$a=\frac{F_{1} +F_{2} }{m}$

$a= \frac{2.05*10^{3} -1.87*10^{3}}{1300}$

a= 0.139 m/s²

b) Kinematics of the boat

Because the boat moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+at Formula (3)

Where:

d:displacement in meters (m)

t : time interval (s)

v₀: initial speed (m/s)

vf: final speed (m/s)

a: acceleration (m/s² )

Data

v₀ = 0

a= 0.139 m/s²

t = 8 s

Calculation of the distance traveled by the boat in 8 s

We replace data in the formula (2)

d= v₀t+ (1/2)*a*t²

d= 0+ (1/2)*(0.139)*(8)²

d= 4.45 m

c) Calculation of the speed of the boat in 8 s

We replace data in the formula (3):

vf= v₀+at

vf= 0+( 0.139)*(8)

vf= 1.1 m/s

6 0

4 years ago