The answer is letter C. 1.2 10^-11 N up
Solution:
F= Bqvsin(theta)
theta = sin 90 = 1
F= 1.4 T * 1.6x10^-19 * 5.2x10^7 ms^-1
F= 1.16 x 10^-11 N
Then the direction is upward.
Explanation:
a. The velocity of the wind as a vector in component form will be represented as v vector:

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

c. The true velocity of the jet as a vector will be represented as w:


d. The true speed of the jet will be calculated as:




e. The direction of the jet will be:



Answer:
it is 12.15 km
Explanation:
1215 km ÷1000
=12.15
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<span>A good conductor have lots of free electrons present in it As due to very less difference between valence band and conductive band so electrons can be easily available for conducting electricity
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