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Shtirlitz [24]
3 years ago
11

In a galvanic cell,a oxidation occurs at the (name of electrode)b.the cathode is the (sign) electrodec.cations flow in solution

toward the (name of electrode)d.electrons flow from the (name of electrode) to (name of electrode)
Chemistry
1 answer:
Tatiana [17]3 years ago
7 0

Answer: a) anode

b) positive

c) cathode

d) anode to cathode

Explanation:

Galvanic cell is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.  Thus the electrons are produced at anode and travel towards cathode.

Due to loss of electrons at anode, positive charge in concentrated in anode and negative charge is concentrated in cathode. To balance these charges , positive ions or cations from salt bridge move towards cathode and negative ions or anions from salt bridge move towards anode.

The balanced two-half reactions will be:

Oxidation half reaction : M(s)\rightarrow M^{n+}(aq)+ne^-

Reduction half reaction : X^{n+}(aq)+ne^-\rightarrow X(s)

Thus the overall reaction will be,

M(s)+X^{n+}(aq)\rightarrow M^{n+}(aq)+X(s)

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What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme
boyakko [2]

<u>Answer:</u> The longest wavelength of light is 656.5 nm

<u>Explanation:</u>

For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.096776\times 10^7m^{-1}

n_f = Higher energy level = n_i+1=(2+1)=3

n_i= Lower energy level = 2    (Balmer series)

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

1m=10^9nm

So, 6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm

Hence, the longest wavelength of light is 656.5 nm

4 0
3 years ago
Visible light waves are part of the blank Spectrum
Ilia_Sergeevich [38]

Visible light spectrum or electromagnetic spectrum

6 0
3 years ago
A compound contains 1.2 g of carbon, 3.2 g of oxygen and 0.2g of hydrogen. Find the formula of the compound
Karolina [17]

Answer:

The empirical formula of the compound is C_{0.504}HO_{1.008}.

Explanation:

We need to determine the empirical formula in its simplest form, where hydrogen (H) is scaled up to a mole, since it has the molar mass, and both carbon (C) and oxygen (O) are also scaled up in the same magnitude. The empirical formula is of the form:

C_{x}HO_{y}

Where x, y are the number of moles of the carbon and oxygen, respectively.

The scale factor (r), no unit, is calculated by the following formula:

r = \frac{M_{H}}{m_{H}} (1)

Where:

m_{H} - Mass of hydrogen, in grams.

M_{H} - Molar mass of hydrogen, in grams per mole.

If we know that  M_{H} = 1.008\,\frac{g}{mol} and m_{H} = 0.2\,g, then the scale factor is:

r = \frac{1.008}{0.2}

r = 5.04

The molar masses of carbon (M_{C}) and oxygen (M_{O}) are 12.011\,\frac{g}{mol} and 15.999\,\frac{g}{mol}, then, the respective numbers of moles are: (r = 5.04, m_{C} = 1.2\,g, m_{O} = 3.2\,g)

Carbon

n_{C} = \frac{r\cdot m_{C}}{M_{C}} (2)

n_{C} = \frac{(5.04)\cdot (1.2\,g)}{12.011\,\frac{g}{mol} }

n_{C} = 0.504\,moles

Oxygen

n_{O} = \frac{r\cdot m_{O}}{M_{O}} (3)

n_{O} = \frac{(5.04)\cdot (3.2\,g)}{15.999\,\frac{g}{mol} }

n_{O} = 1.008\,moles

Hence, the empirical formula of the compound is C_{0.504}HO_{1.008}.

3 0
3 years ago
CAN ANYONE PLEASE HELP MY BOOKS ARENT HELPING!!!! THIS IS FOR FIRE TECH
Mazyrski [523]

Answer:

The answer to the question is;

The occupant load of the store having a floor area of 100,000 ft² is 3,317.86 persons.

Explanation:

Based on NFPA guidelines  we have for sales on street floor, the allowable occupant load factor per person is 30 ft²

That is where  the floor area is 100,000 square feet we have the number of allowable occupant given by

(100,000 ft²)/(30 ft²/Person) = \frac{10000}{3} Persons or 3,333 persons

That is the  occupant load of the store if the floor area is 100,000 square feet = 3,333 persons

Based on m² we have  9,290 m² will require 2.8 m²/person

which gives;

(9,290 m²)/(2.8 m²/person) = \frac{9290}{2.8} Persons = 23225/7 or 3,317.86 persons

Therefore applying safety, we go with the lesser number and we have

The occupant load of the store having a floor area of 9,290 m² = 3,317.86 persons.

5 0
3 years ago
Which statement describes the density of the inner planets?
katrin [286]

Answer:

c

Explanation:

8 0
3 years ago
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