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3 years ago

Please help.

Physics

2 answers:

Vanyuwa [196]3 years ago

7 0

I'm gonna go with unbalanced force because ^^

Lena [83]3 years ago

7 0

An object resting on a table weighs 100 N. So the object is pushing down on the table with 100N of force.

The table is pushing UP on the object with 100N of force.

There are two reasons for saying this. They both come from Newton's laws of motion:

-- From Newton's 3rd law: For every action, there is an equal and opposite reaction. If the object pushes the table, down, with 100N of force, then the table pushes the object, up, with 100N of force. THERE's your pair of equal, opposite forces, and Newton is happy.

-- From Newton's 2nd law: The net force on an object is equal to the mass of the object multiplied by its acceleration. Imagine a piece of paper slipped in between the object and the table. The paper is not accelerating, so the net force on it must be zero. If the object is pushing down on the paper with 100/N of force, then ... in order for the net force on the paper to be zero ... the table must be pushing up on the paper with 100N of force.

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What is the mass of a rock lifted 2 meters off the ground that has 196 J of potential energy?

eimsori [14]

Answer:

10kg

Explanation:

Let PE=potential energy

PE=196J

g(gravitational force)=9.8m/s^2

h(change in height)=2m

m=?

PE=m*g*(change in h)

196=m*9.8*2

m=10kg

4 0

3 years ago

Which of these would most likely be a parts of a lab procedure?

vladimir2022 [97]

C . Record the time to complete a chemical reaction

6 0

3 years ago

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Using a 683 nm wavelength laser, you form the diffraction pattern of a 1.1 mm wide slit on a screen. You measure on the screen t

n200080 [17]

Answer:

10.2 m

Explanation:

The position of the dark fringes (destructive interference) formed on a distant screen in the interference pattern produced by diffraction from a single slit are given by the formula:

$y=\frac{\lambda (m+\frac{1}{2})D}{d}$

where

y is the position of the m-th minimum

m is the order of the minimum

D is the distance of the screen from the slit

d is the width of the slit

$\lambda$ is the wavelength of the light used

In this problem we have:

$\lambda=683 nm = 683\cdot 10^{-9} m$ is the wavelength of the light

$d=1.1 mm = 0.0011 m$ is the width of the slit

m = 13 is the order of the minimum

$y=8.57 cm = 0.0857 m$ is the distance of the 13th dark fringe from the central maximum

Solving for D, we find the distance of the screen from the slit:

$D=\frac{yd}{\lambda(m+\frac{1}{2})}=\frac{(0.0857)(0.0011)}{(683\cdot 10^{-9})(13+\frac{1}{2})}=10.2 m$

6 0

4 years ago

In Thomson’s experiment, why was the glowing beam repelled by a negatively charged plate?

Svetllana [295]

The glowing beam was repelled by a negatively charged plate because they were negatively charged

<h3>What are the nature of charges?</h3>

The nature of charges refers to the properties of charges.

There are two types of charges:

negative charges
positive charges

The law of electricity states that opposite charges attract whereas like charges repel.

Therefor, in Thomson’s experiment, the glowing beam was repelled by a negatively charged plate because they were negatively charged

In conclusion, like charges repel while opposite charges attract.

Learn more about charges at: brainly.com/question/12781208

#SPJ1

5 0

2 years ago

HEY CAN ANYONE PLS PLS PLS HELP ME OUT IN DIS I AM STRUGGLING TOO MUCH

meriva

<h3>Answer: 104.5 cubic cm</h3>

=======================================================

Work Shown:

r = radius = 1.045 cm

h = height = 30.48 cm

pi = 3.141 approximately

V = volume of cylinder

V = pi*r^2*h

V = 3.141*(1.045)^2*30.48

V = 104.547940002

V = 104.5 cubic cm

6 0

3 years ago