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3 years ago

Please help.

Physics

2 answers:

Vanyuwa [196]3 years ago

7 0

I'm gonna go with unbalanced force because ^^

Lena [83]3 years ago

7 0

An object resting on a table weighs 100 N. So the object is pushing down on the table with 100N of force.

The table is pushing UP on the object with 100N of force.

There are two reasons for saying this. They both come from Newton's laws of motion:

-- From Newton's 3rd law: For every action, there is an equal and opposite reaction. If the object pushes the table, down, with 100N of force, then the table pushes the object, up, with 100N of force. THERE's your pair of equal, opposite forces, and Newton is happy.

-- From Newton's 2nd law: The net force on an object is equal to the mass of the object multiplied by its acceleration. Imagine a piece of paper slipped in between the object and the table. The paper is not accelerating, so the net force on it must be zero. If the object is pushing down on the paper with 100/N of force, then ... in order for the net force on the paper to be zero ... the table must be pushing up on the paper with 100N of force.

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In the long jump, an athlete launches herself at an angle above the ground and lands at the same height, trying to travel the gr

NikAS [45]

A) 2.64t

B) 2.64h

C) 2.64D

Explanation:

The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

The time of flight of a projectile can be found from the equations of motion, and it is found to be

$t=\frac{2u sin \theta}{g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the time of flight is $t$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:

$t'=\frac{2usin \theta}{g'}=\frac{2u sin \theta}{0.379g}=\frac{1}{0.379}t=2.64t$

The maximum height reached by a projectile can be also found using the equations of motion, and it is given by

$h=\frac{u^2 sin^2\theta}{2g}$

where

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the maximum height is $h$ .

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:

$h'=\frac{u^2 sin^2\theta}{2g'}=\frac{u^2 sin^2\theta}{(0.379)2g}=\frac{1}{0.379}h=2.64h$

The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by

$D=\frac{u^2 sin(2\theta)}{g}$

where:

u is the initial speed

$\theta$ is the angle of projection

g is the acceleration due to gravity

In this problem, when the athlete is on the Earth, the horizontal distance covered is D.

When she is on Mars, the acceleration due to gravity is:

$g'=0.379 g$

where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be:

$D'=\frac{u^2 sin(2\theta)}{g'}=\frac{u^2 sin(2\theta)}{(0.379)g}=\frac{1}{0.379}D=2.64D$

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3 years ago

If you pour different liquids into a graduated cylinder, which layer would be at the bottom?

klasskru [66]

the one that is more dense!

5 0

3 years ago

Who invented the first telescope

mylen [45]

Answer:

Hans Lipperhey

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2 years ago

Read 2 more answers

Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe

deff fn [24]

Answer:

$\theta_2 - \theta_1 = 156.93 degree$

Explanation:

As we know that the displacement of the particle from the mean position is 1/5 times of its amplitude

so we have

$y = A sin\omega t$

$y = \frac{A}{5}$

so now we have

$\frac{A}{5} = A sin\omega t$

now we have

$\theta_1 = 11.53 degree$

so the phase other particle in opposite direction is given as

$\theta_2 = 180 - 11.53 = 168.46 degree$

so we have phase difference given as

$\theta_2 - \theta_1 = 168.46 - 11.53$

$\theta_2 - \theta_1 = 156.93 degree$

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3 years ago

Which of the following is not an element of installment credit?

Alex787 [66]

Answer:

c line of credit I believe

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2 years ago