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BlackZzzverrR [31]
3 years ago
6

1.A worker pulls horizontally on a crate across a rough horizontal surface, causing it to move forward with constant velocity. F

orce A is the force exerted by the worker and force B is the force of friction due to the surface. What is the relationship between A and B?
A = B

A< B

A > B

2. In a color picture tube, an electric field exerts a net force of magnitude 1.60 × 10-13 N on an electron. The rest mass of an electron is 9.11 × 10-31 kg. What is the electron's accceleration?

1.76 × 1017 m/s2

1.96 × 1024 m/s2

1.45 × 1043 m/s2

1.60 × 10-13 m/s2
Physics
1 answer:
Ymorist [56]3 years ago
4 0

1. Answer:

The relationship between Force A and Force B is given as:

A = B

Explanation:

To produce acceleration to a body, an unbalanced force must be applied. Meaning that a Force must be applied to the body greater than that of Force of Friction.

In our case, a Force A is exerted on the crate which is moving with a constant velocity. As there is no acceleration, the force applied must be equal to the force of Friction B.

2. Answer:

The electron's acceleration is 1.756 x 10¹⁷ ms⁻².

Explanation:

Electric field exerts a Force on the electron given as:

F = 1.6 x 10⁻¹³ N

Rest mass of electron = 9.11 x 10⁻³¹ kg

According to newton's 2nd law of motion, a net force F applied on the electron must produce an acceleration 'a' which is directly proportional to the Force and inversely proportional to the rest mass of the electron given as:

a = F/m

a = (1.6 x 10⁻¹³)/(9.11 x 10⁻³¹)

a = 1.756 x 10¹⁷ ms⁻²

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A wheel is being turned to open a valve on a compressor. The resistance that is applied to the axle of the valve is 235 lb. The
SIZIF [17.4K]

Answer:

3.8 in

Explanation:

A wheel and axle machine is a machine in which the wheel rotates around the rod (axle). They rotate together thereby transferring force among each other.

The formula for a wheel and axle is:

Fr * Rr = Fe * Re

Where Fr is the resistance force, Rr is the radius of the resistance force, Fe is the effort force and Re is the radius of the resistance force.

Given that: Fr = 235 lb, Fe = 45 lb, Re = 20 in / 2 = 10 in. Hence:

235 * Rr = 45 * 10

Rr = 45 * 10 / 235

Rr= 1.9 in

Diameter of axle = 2 * 1.9 = 3.8 in

3 0
3 years ago
A box full of stuff was pushed for 500 N at 15 m/s2. What is the mass of the box?
stepladder [879]
F = ma
500 = m x 15
m = 33.33 kg
8 0
3 years ago
what are valence shell electrons?a. electrons thata re unchargedb. electrons that are positively chargedc. electrons that are av
goblinko [34]
Your answer is c. electrons that are available for bonding.
6 0
3 years ago
a pitcher throws a .015 kg baseball from rest to a final velocity of 45. what is the magnitude of the change in momentum of the
BabaBlast [244]

Answer:

0.675 kg m/s

Explanation:

Momentum = mass x velocity

= 0.015 x 45 = 0.675 kg m/s

P.S. I'm not sure of this answer,  so it might be a good idea to check this with some other sources.

6 0
3 years ago
X-rays with an energy of 301 keV undergo Compton scattering with a target. If the scattered X-rays are detected at 77.5^{\circ}
Alex73 [517]

Answer:

6.03\cdot 10^{-12} m

Explanation:

First of all, we need to find the initial wavelength of the photon.

We know that its energy is

E=301 keV = 4.82\cdot 10^{-14}J

So its wavelength is given by:

\lambda = \frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.82\cdot 10^{-14} J}=4.13\cdot 10^{-12}m

The formula for the Compton scattering is:

\lambda' = \lambda +\frac{h}{mc}(1-cos \theta)

where

\lambda is the original wavelength

h is the Planck constant

m is the electron mass

c is the speed of light

\theta=77.5^{\circ} is the angle of the scattered photon

Substituting, we find

\lambda' = 4.13\cdot 10^{-12} m +\frac{6.63\cdot 10^{-34} Js)}{(9.11\cdot 10^{-31}kg)(3\cdot 10^8 m/s)}(1-cos 77.5^{\circ})=6.03\cdot 10^{-12} m

7 0
3 years ago
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