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4 years ago

Differentiate gravitational force and acceleration due to gravity

Physics

1 answer:

julia-pushkina [17]4 years ago

8 0

Answer:

I hope this answer is correct

Explanation:

Difference Between Gravitation and Gravity

Gravitation is referred to the force acting between two bodies which can be represented as the F=(GM1M2)/R2 which means gravitation force is proportional to the product of the masses of the object 1 and object 2 and is inversely proportional to the square of the distance between them. The gravitational force between earth and any object is known as gravity.

Difference Between Gravitation and Gravity

Gravitation Gravity

It is a universal force It is not a universal force

It is a weak force It is a strong force

The force is F=(GM1M2)/R2 (G= gravitational constant) The force is F=mg (g=acceleration due to gravity)

The direction of gravitational force lies in the radial direction from the masses The direction of the force of gravity is along the line joining the earth’s center and the center of the body. Its direction is towards the center of the earth.

The force can be 0 when the separation between bodies is infinity The force of gravity can be 0 at the center of the earth

It requires two masses It requires only one mass

These were some difference between Gravitation and Gravity. If you wish to find out more, download BYJU’S The Learning App.

Gravity Acceleration Due to Gravity

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3 years ago

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Explanation:

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Velocity at t = 0

$v(0)=-2\ m/s$

Velocity is given by

$v(t)=\int a(t)dt\\\Rightarrow v(t)=\int 6sin(t)dt\\\Rightarrow v(t)=6\int sin(t)\\\Rightarrow v(t)=-6cost+C$

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3 years ago

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Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.

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3 years ago

Determine the magnitude of the resultant force acting on a 5 −kg particle at the instant t=2 s, if the particle is moving along

Alex787 [66]

Answer:

F = 296.7N

Explanation:

The x and y component of the position vector are given by:

$x(t) =rcos\phi, y(t) = rsin\phi\\ \frac{dx}{dt} =\frac{dr}{dt} cos\phi - rsin\phi\frac{d\phi}{dt} , \frac{dy}{dt}=\frac{dr}{dt}sin\phi + rcos\phi\frac{d\phi}{dt}\\ \frac{d^2x}{dt^2} = \frac{d^2r}{dt^2} cos\phi - \frac{dr}{dt} sin\phi\frac{d\phi}{dt} -\frac{dr}{dt} sin\phi\frac{d\phi}{dt} - r(cos\phi\frac{d^2\phi}{dt^2} + sin\phi\frac{d^2\phi}{dt^2})$

$\frac{d^2y}{dt^2} = \frac{d^2r}{dt^2} sin\phi + \frac{dr}{dt} cos\phi\frac{d\phi}{dt}+\frac{dr}{dt}cos\phi\frac{d\phi}{dt}+r(-sin\phi\frac{d^2\phi}{dt^2} +cos\phi\frac{d^2\phi}{dt^2})$

At t = 2s:

$\phi(2) = 1.5t^2-6t= -6\\ \frac{d\phi}{dt}(2) = 3t-6=0\\ \frac{d^2\phi}{dt^2}=3\\r(2)=2t+10=14\\ \frac{dr}{dt}=2\\\frac{d^2r}{dt^2} = 0$

Plugging in:

$\frac{d^2x}{dt^2}=-42(cos(-6) + sin(-6))=-52\frac{m}{s^2} \\\frac{d^2y}{dt^2} = 42(cos(-6)-sin(-6))=28.6\frac{m}{s^2}$

The resulting force F is:

$F = m\sqrt{(\frac{d^2x}{dt^2})^2 + (\frac{d^2y}{dt^2})^2}=296.7N$

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3 years ago

Differentiate gravitational force and acceleration due to gravity​

Differentiate gravitational force and acceleration due to gravity