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Free_Kalibri [48]
3 years ago
9

In this problem, you will practice applying this formula to several situations involving angular acceleration. in all of these s

ituations, two objects of masses m1 and m2 are attached to a seesaw. the seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction.assume that the pivot is attached tot he center of the bar. you are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. in all cases, assume that m1>m2.
Physics
1 answer:
MatroZZZ [7]3 years ago
6 0
<span>A- 2*[(m1 - m2)/(m1 + m2)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive. B- 2*[(m1 - m2)/(m1+ m2 +mbar/3)]*g/L The rotation is in the counterclockwise direction and the angular acceleration is positive.</span>
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A car has a kinetic energy of 432,000 J when traveling at a speed of 23 m/s. What is its mass?
gladu [14]

Answer:

2

Explanation:

2

8 0
3 years ago
Draw a picture of an atom.include protons,neutrons, and electrons.
gogolik [260]
Hey, unfortunately it’s impossible for me to draw one for you here, but you should be able to draw it yourself pretty easily!

Answer:


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Hope this helps
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4 years ago
Help plz 100 points and guaranteed Brainliest
nadezda [96]

Answer:

Guy above is correct on everything!

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The rate of rotation of the disk is gradually increased. The coefficient of static friction between the coin and the disk is 0.5
MrRissso [65]

Question is not complete and the missing part is;

A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center. The disk rotates at a constant rate in a counterclockwise direction. The coin does not slip, and the time it takes for the coin to make a complete revolution is 1.5 s.

Answer:

0.828 m/s

Explanation:

Resolving vertically, we have;

Fn and Fg act vertically. Thus,

Fn - Fg = 0 - - - - eq(1)

Resolving horizontally, we have;

Ff = ma - - - - eq(2)

Now, Fn and Fg are both mg and both will cancel out in eq 1.

Leaving us with eq 2.

So, Ff = ma

Now, Frictional force: Ff = μmg where μ is coefficient of friction.

Also, a = v²/r

Where v is linear speed or velocity

Thus,

μmg = mv²/r

m will cancel out,

Thus, μg = v²/r

Making v the subject;

rμg = v²

v = √rμg

Plugging in the relevant values,

v = √0.14 x 0.5 x 9.8

v = √0.686

v = 0.828 m/s

3 0
3 years ago
What is the average speed of an object that travels 400 meters in 80 seconds?
AnnyKZ [126]

Answer:

<h2>5 m/s</h2>

Explanation:

The average speed of the object can be found by using the formula

v =  \frac{d}{t}  \\

d is the distance

t is the time taken

From the question we have

v =  \frac{400}{80}  =  \frac{40}{8}  \\

We have the final answer as

<h3>5 m/s</h3>

Hope this helps you

4 0
3 years ago
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