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3 years ago

The Sun is a yellow star that's both average in brightness and temperature and is classified as

Chemistry

1 answer:

Roman55 [17]3 years ago

7 0

Answer:

Classifying stars according to their spectrum is a very powerful way to begin to understand how they work. As we said last time, the spectral sequence O, B, A, F, G, K, M is a temperature sequence, with the hottest stars being of type O (surface temperatures 30,000-40,000 K), and the coolest stars being of type M (surface temperatures around 3,000 K). Because hot stars are blue, and cool stars are red, the temperature sequence is also a color sequence. It is sometimes helpful, though, to classify objects according to two different properties. Let's say we try to classify stars according to their apparent brightness, also. We could make a plot with color on one axis, and apparent brightness on the other axis, like this:

Explanation:

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If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the

uysha [10]

Answer:

2.01 M

Explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

$36.2g \times \frac{1mol}{60.05g} = 0.603mol$

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

$300mL \times \frac{1L}{1000mL} = 0.300L$

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

$M = \frac{0.603mol}{0.300L} = 2.01 M$

7 0

3 years ago

Hi, can someone help me with chemistry

Dominik [7]

Idk look it up on another website

6 0

3 years ago

How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?

AURORKA [14]

Answer:

0.02 mol.

Explanation:

8 0

3 years ago

Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH

gtnhenbr [62]

Answer: The number of moles of $CaC_2$ reacted was 0.229

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = Total pressure - vapor pressure of water = (749 - 23.8) mm Hg= 725.2 mm Hg = 0.954 atm (760mmHg= 1atm)

V = Volume of gas = 5.87 L

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $25^0C=(25+273)K=298K$

$n=\frac{PV}{RT}$

$n=\frac{0.954atm\times 5.87L}{0.0821 L atm/K mol\times 298K}=0.229moles$

$CaC_2(s)+2H_2O(l)\rightarrow C_2H_2(g)+Ca(OH)_2(aq)$

According to stoichiometry:

1 mole of $C_2H_2$ is produced by = 1 mole of $CaC_2$

Thus 0.229 moles of $C_2H_2$ is produced by = $\frac{1}{1}\times 0.229=0.229$ moles of $CaC_2$

Thus number of moles of $CaC_2$ reacted was 0.229

5 0

3 years ago

A solution of pH 3 was mixed with a solution of pH 9. What is the final pH could be ?

chubhunter [2.5K]

The solution of which contains of PH 3 called acidic medium which is more stronger acid called HCl when reacts to the stronger base base NaOH forms the acid base reaction .

According to acid base equation you consider ph5 as PH 9 if you understand it then tell me below

3 0

3 years ago