Answer:
163.94
Explanation:
Na = 22.99 (3)
P = 30.97
O = 16.00 (4)
22.99(3) + 30.97 +16.00(4) = 163.94
Hope that helps
Nonmetals is most likely the answer
The reaction for the formation of MgO(s):
2 Mg (s) + O2(g) -à
2MgO(s) ΔH = -601.24
kJ/mol
<span>The enthalpy
information is taken from: http://webbook.nist.gov/cgi/inchi?ID=C1309484&Mask=2</span>
From the equation and with an enthalpy change of -231 kJ:
-231 kJ * 2 mol Mg * (1/-601.24 kJ/mol) = 0.76841 mol Mg
Then, with the molar mass of MgO = 40.3,
0.76841 mol Mg *(2 mol MgO/2 mol Mg)* 40.3 g/mol MgO = <span>30.967 g MgO</span>
Answer:
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
Explanation:
We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.
Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.
In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
I am typing this to get more answers for one of my tests good luck dawg
