An apartment has two fire alarms. In the event of a fire, the probability that alarm A will fail is 0.004, and the probability t
hat alarm B will fail is 0.01. Assume the two failures are independent, what is the probability that at least one alarm fails in the event of a fire
1 answer:
Answer: 0.0136
Step-by-step explanation:
Let events are:
A = alarm A will fail
B= alarm B will fail
We have given ,
P(A) = 0.004 , P(B)=0.01
Since both events are independent , so
P(A and B) = P(A) x P(B)
= 0.04 x 0.01 =0.0004
i.e. P(A and B) =0.0004
Now , P(A or B) = P(A)+P(B)-P(A and B)
= 0.004+ 0.01-0.0004=0.0136
Hence, the probability that at least one alarm fails in the event of a fire is 0.0136 .
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