All categories

3 years ago

1. Describe what Rutherford’s model of an atom looks like .

Chemistry

1 answer:

andreyandreev [35.5K]3 years ago

3 0

1.Rutherford's atom has a small, dense nucleus that is positively charged, contains 1 proton, contains neutrons...

I believe this is it....

Hope this helps...

You might be interested in

Does anybody know the answer to these two questions ?

Serjik [45]

the first is hydroxide. I believe d is the second one but I'm not 100% positive so you may want to get a second opinion

4 0

3 years ago

Omg pls help i dunno what the frick frack this is

snow_lady [41]

Answer:

1. Mass of KCl produced = 774.8 g of KCl

2. Mass of KNO₃ produced = 13.837g

3. Moles of NaOH made = 0.846 moles

4. Moles of LiCl produced = 0.846 moles

5. Moles of CO₂ produced = 207.6 moles

Explanation:

1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.

5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl

Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol

10.4 moles of KCl = 10.4 × 74.5 g

Mass of KCl produced = 774.8 g of KCl

2. Mole ratio of KNO₃ and KOH = 1:1

O.137 moles of KOH will produce 0.137 moles of KNO₃

Molar mass of KNO₃ = 101 g/mol

Mass of KNO₃ produced = 0.137 × 101 g = 13.837g

3. Molar mas of Ca(OH)₂ = 74.0 g

Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂

Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1

Moles of NaOH made = 2 × 0.423 = 0.846 moles

4. Molar mass of MgCl₂ = 95.0 g

Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles

From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2

Moles of LiCl produced = 2 × 0.423 = 0.846 moles

5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂

34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂

Moles of CO₂ produced = 207.6 moles

4 0

2 years ago

Select the answer that lists the radiation waves in order of increasing

lubasha [3.4K]

D. microwaves, Ultraviolet, x-rays

3 0

3 years ago

Read 2 more answers

The average speed of oxygen molecules in air is about ____. (1 point) 0 km/h 170 km/h 1700 km/h 17,000 km/h

LenKa [72]

The average speed is calculated using the following formula $speed = \sqrt{\frac{3kT}{m} }$

Where

$k = 1.381 X 10^{-23} J / K$

T = 298 K [room temperature]

m = mass of each molecule of oxygen

mass of one mole of oxygen molecules = 32 g / mol

mass of one molecule of oxygen will be = $\frac{32}{6.023 X 10^{23} }$

mass of one molecule of oxygen will be = $5.31 X 10^{-23} g = 5.31 X 10^{-26} kg$

putting values

average speed = $\sqrt{\frac{3 X 1.381 X 10^{-23} X 298}{5.31 X 10^{-26} kg} }$

Average speed = 482.19 m / s

average speed = 1735.8 km / h

so approx = 1700 km/h

4 0

3 years ago

Read 2 more answers

Calcular la cantidad de NaOH necesaria para preparar medio litro de disolución 2,5 N. (Dato: peso molecular del NaOH = 40 g/mol)

kolbaska11 [484]

Answer:

The amount of NaOH required to prepare a solution of 2.5N NaOH.

The molecular mass of NaOH is 40.0g/mol.

Explanation:

Since,

NaOH has only one replaceable -OH group.

So, its acidity is one.

Hence,

The molecular mass of NaOH =its equivalent mass

Normality formula can be written as: $Normality=\frac{mass of solute NaOH}{its equivalent mass} * \frac{1}{volume of solution in L} \\$

Substitute the given values in this formula to get the mass of NaOH required.

$2.5N=\frac{mass of NaOH}{40g/mol} *\frac{1}{1L} \\mass of NaOH=2.5N*40gmol\\ = 100.0g$

Hence, the mass of NaOH required to prepare 2.5N and 1L. solution is 100g

8 0

2 years ago