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2 years ago

Please be quick, i need this as soon as possible!

Mathematics

2 answers:

dalvyx [7]2 years ago

7 0

Answer:

I’m pretty sure the answer is a

Step-by-step explanation:

nikitadnepr [17]2 years ago

3 0

Answer:

its -1.5 and you use answer

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PLEASE HELP ILL GIVE BRAINLIESTTTT :)

Taya2010 [7]

Answer:

Yes, these triangles are congruent

∠E≅∠M

Step-by-step explanation:

Yes, these triangles are similar.

Proof:

Each side in LNM is $1\frac{2}{3}$ times longer than the sides in GFE

$30/18 = 1\frac{2}{3}$

$25/15=1\frac{2}{3}$

$20/12 = 1\frac{2}{3}$

According CPCTC (corresponding parts of congruent triangles are congruent), angle E is similar to angle M.

Hope this helps :)

Have a good day!

4 0

2 years ago

What is the first step for solving the inequality 3y+14=44

uranmaximum [27]

3y+14=44

Answer: First step is to subtract 14 from each side

3y = 30 (divide each side by 3)
y = 30/3, y = 10

7 0

2 years ago

Find the surface area of the prism 9mm 12mm 8mm

TEA [102]

We are asked in this problem the surface area of the prism given the dimensions: 9mm by 12mm by 8mm. Surface area is the sum of the areas of each face of the prism. The formula for surface area is 2*lw+2*lh+ 2*wh. In this case, upon substitution, SA = 2*9*12+2*9*8+2*12*8 equal to a total of 552 mm2.

7 0

3 years ago

Read 2 more answers

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

2 years ago

What is the domain and range of f(x)=4^x-8

gladu [14]

If the function is: f(x) = 4^x - 8

D = {XeR}
R = {YeR|Y≥0}

if the function is: f(x)=4^(x-8)

D = {XeR}
R = {YeR|Y≥ -8}

8 0

2 years ago