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miskamm [114]
3 years ago
8

Electrons carry energy from a battery to a lightbulb.

Physics
2 answers:
riadik2000 [5.3K]3 years ago
5 0
The correct answer among all the other choices is "None of the above." <span>Electrons carry energy from a battery to a light bulb. The electron's potential energy will be converted into light energy. </span>Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
Gwar [14]3 years ago
4 0

Answer:

None of the above.

Explanation:

In a lightbulb, electrons at higher potential energy enter the lightbulb and give off that energy as they pass through the bulb. The number of electrons exiting and entering the bulb is the same. As electrons pass through the lightbulb, heat is produced due to the current,  this makes the filament of the lightbulb to incandescence, and that is the light we see.

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A charge of 1. 5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How
ELEN [110]

It is a type capacitor is in which two metal plates arranged in such a way so that they are connected in parallel . The potential energy is stored in the capacitor will be 2.7×10⁻⁵.

<h3>What is parallel plate capacitor ?</h3>

It is an type capacitor is an in which two metal plates arranged in such a way so that they are connected in parallel and have some distance between them.

A dielectric medium is a must in between these plates. helps to stop the flow of electric current through it due to its non-conductive nature .

The given data in the problem is;

Q is the charge= 1.5 µC

V is the change in voltage across the plates is = 36 V.

U is the potential energy=?

The formula for the potential energy is given by;

\rm U= \frac{1}{2} \times Q \times V \\\\ \rm U= \frac{1}{2} \times 1.5\times 10^{-6} \times 36 \\\\  \rm U=2.7\times10^{-5}

Hence the potential energy is stored in the capacitor will be 2.7×10⁻⁵.

To learn more about the parallel plate capacitor refer to the link;

brainly.com/question/12883102

3 0
2 years ago
How do cells maintain homeostasis
Vikki [24]

Answer:

because they become home for them when they are in there for such a along time

5 0
3 years ago
A solution is prepared by dissolving 17.75 g sulfuric acid, h2so4, in enough water to make 100.0 ml of solution. if the density
Yuliya22 [10]

The solution of Sulfuric Acid (H2SO4) has the following mole fractions:

  • mole fraction (H2SO4)= 0.034
  • mole fraction (H2O)= 0.966

To solve this problem the formula and the procedure that we have to use is:

  • n = m / MW
  • = ∑ AWT
  • mole fraction = moles of A component / total moles of solution
  • ρ = m /v

Where:

  • m = mass
  • n = moles
  • MW = molecular weight
  • AWT = atomic weight
  • ρ = density
  • v = volume

Information about the problem:

  • m solute (H2SO4) = 17.75 g
  • v(solution) = 100 ml
  • ρ (solution)= 1.094 g/ml
  • AWT (H)= 1 g/mol
  • AWT (S) = 32 g/mol
  • AWT (O)= 16 g/mol
  • mole fraction(H2SO4) = ?
  • mole fraction(H2O) = ?

We calculate the moles of the H2SO4 and of the H2O from the Pm:

MW = ∑ AWT

MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4

MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)

MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol

MW (H2SO4)=  98 g/mol

MW (H2O)= AWT (H) * 2 + AWT (O)

MW (H2O)= (1 g/mol * 2) + (16 g/mol)

MW (H2O)= 2 g/mol + 16 g/mol

MW (H2O)=  18 g/mol

Having the Pm we calculate the moles of H2SO4:

n = m / MW

n(H2SO4) = m(H2SO4) / MW (H2SO4)

n(H2SO4) = 17.75 g / 98 g/mol

n(H2SO4) = 0.1811 mol

With the density and the volume of the solution we get the mass:

ρ(solution)= m(solution) /v(solution)

m(solution) = v(solution) * ρ(solution)

m(solution) = 100 ml * 1.094 g/ml

m(solution) = 109.4 g

Having the mass of the solution we calculate the mass of the water in the solution:

m(H2O) = m(solution) - m solute (H2SO4)

m(H2O) = 109.4 g - 17.75 g

m(H2O) = 91.65 g

We calculate the moles of H2O:

n = m / MW

n(H2O) = m(H2O) / MW (H2O)

n(H2O) = 91.65 g / 18 g/mol

n(H2O) = 5.092  mol

We calculate the total moles of solution:

total moles of solution = n(H2SO4) + n(H2O)

total moles of solution = 0.1811 mol + 5.092  mol

total moles of solution = 5.2731 mol

With the moles of solution we can calculate the mole fraction of each component:

mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution

mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol

mole fraction (H2SO4)= 0.034

mole fraction (H2O)= moles of (H2O) / total moles of solution

mole fraction (H2O)= 5.092  mol / 5.2731 mol

mole fraction (H2O)= 0.966

<h3>What is a solution?</h3>

In chemistry a solution is known as a homogeneous mixture of two or more components called:

  • Solvent
  • Solute

Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161

#SPJ4

8 0
2 years ago
Help ME QUICK PLEASE QUESTION 2 AND 4 PLEASE 58 POINTS
monitta

Answer:

For number 4: A vector pointing to the right with a magnitude of 2.0

Explanation:

Very simple- just subtract 6-2

I am not sure how to do #2- sorry!

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3 years ago
Help for physical science u4 limiting reactants
Yuliya22 [10]
The reactants are on the left and the products are on the right of the equation
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