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2 years ago

Electrons carry energy from a battery to a lightbulb.

2 answers:

riadik2000 [5.3K]2 years ago

5 0

The correct answer among all the other choices is "None of the above." <span>Electrons carry energy from a battery to a light bulb. The electron's potential energy will be converted into light energy. </span>Thank you for posting your question. I hope this answer helped you. Let me know if you need more help.

Gwar [14]2 years ago

4 0

Answer:

None of the above.

Explanation:

In a lightbulb, electrons at higher potential energy enter the lightbulb and give off that energy as they pass through the bulb. The number of electrons exiting and entering the bulb is the same. As electrons pass through the lightbulb, heat is produced due to the current, this makes the filament of the lightbulb to incandescence, and that is the light we see.

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1 year ago

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A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides . What is the total surface area of th

Stels [109]

Complete Question

Question 18 (3 points) Solve the problem. (3 points) A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides 2.4m, 2. 3m, 1.5 m. What is the total surface area of the reflector?

A) 33 m2

B) 86 m2

C) 52 m2

D) 34 m2

Answer:

The value is $Area =2.78 \ m^2$

Explanation:

From the question we are told that

The sides are a = 2.4 m

b = 2.3 m

c = 1.5 m

Generally the semi perimeter is mathematically represented as

$s = \frac { a + b + c }{2 }$

=> $s = \frac { 2.4 + 2.3 + 1.5 }{2 }$

=> $s =3.1 \ m$

Generally the using Heron's formula we have that the surface are a is mathematically represented as

$Area = \sqrt{S (S - a) (S - b )(S - c ) }$

=> $Area = \sqrt{3.1 (3.1 - 2.4) (3.1 - 2.3 )(3.1 - 1.5 ) }$

=> $Area =2.78 \ m^2$

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belka [17]

Answer:

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Explanation:

I'm in forensic science :)

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2 years ago