What rate do things fall to Earth?
1 answer:
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Answer:
x = 0.327 m
Explanation:
Block 2 of mass 1.00 kg is at rest
spring constant = 200 N/m
Block 1 of mass 2 kg moving at 4 m/s
m₁ v₁ = (m₁ + m₂)V
2 x 4 = (2 + 1) V
V = 2.67 m/s
loss of kinetic energy = gain elastic potential energy
x = 0.327 m
hence, the spring compressed distance is equal to x = 0.327 m
A) Acceleration in part A:
B) Acceleration in part B:
C) Acceleration in part C:
Explanation:
A)
The picture of the problem is missing: find it in attachment.
The acceleration of a body is equal to the rate of change of its velocity:
where
v is the final velocity
u is the initial velocity
is the time it takes for the velocity to change from u to v
In part A of the race, we have:
u = 0
v = 5.5 m/s (estimate)
So the acceleration is
B)
In part B of the race, we have:
u = 5.5 m/s is the initial velocity (estimate)
v = 9.5 m/s is the final velocity (estimate)
is the time interval between the two points considered
Therefore, using the equation for the acceleration, we can find the acceleration in part B:
C)
In part C of the race, we have:
u = 9.5 m/s is the initial velocity (estimate)
v = 11 m/s is the final velocity (estimate)
is the time interval between the two points considered
And therefore, the acceleration in part C of the race is:
Learn more about acceleration:
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