Because the specific metals aren’t mentioned in this inquiry.
The educational guesses that we can propose is that:
<span><span>1. </span>The
hypothetical inquiry: There are existing metals for making pots that will cook
food much faster.</span>
<span><span>2. </span>The
one-tailed alternative hypothesis: There are other metals for making pots that
will cook food much faster than the other metals.</span>
<span><span>
3. </span>The
one-tailed null hypothesis: All metals that are used in making pots will cook
food at an equal rate.</span>
Answer:mile
Explanation: heres a hint think aboyt the distance between your house to school
The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as
- t=0.476v
- t=1.967v
- V2=4.323v
<h3>What is the potential across the capacitor?</h3>
Question Parameters:
A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.
at
- t = 1.0 seconds
- 5.0 seconds
- 20.0 seconds.
Generally, the equation for the Voltage is mathematically given as
v(t)=Vmax=(i-e^{-t/t})
Therefore
For t=1
V=5(i-e^{-1/10})
t=0.476v
For t=5s
V2=5(i-e^{-5/10})
t=1.967
For t=20s
V2=5(i-e^{-20/10})
V2=4.323v
Therefore, the values of voltages at the various times are
- t=0.476v
- t=1.967v
- V2=4.323v
Read more about Voltage
brainly.com/question/14883923
Complete Question
A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.
Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.
1. Heat raises the temperature.
2. It increases volume.
3. It changes state.
4. Brings about chemical action.
5. Changes physical properties.
<h3>Hope this helps :)</h3>
R = ρ L/A. R= resistance, ρ= resistivity, L= length of the conductor. A = area of the conductor. Resistance is directly proportional to the length of the conductor. So if length of the conductor is decreased, resistance will also decrease. Hence A is the correct option