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Savatey [412]
2 years ago
7

Iron has a density of 7.86g/cm^3. Could a block of metal with a mass of 18.2g and a volume of 2.56cm^3 be iron? Show work and ex

plain.
Chemistry
2 answers:
Reptile [31]2 years ago
6 0

Mass=18.2g

Volume=2.56cm^3

=> Density =

=  >  \frac{mass}{volume}

=> Density=

\frac{18.2}{2.56}

=> Density=

7.1g/cm {}^{3}

hjlf2 years ago
5 0

First calculate density of the the metal (should equal to density of iron)

  • Mass=18.2g
  • Volume=2.56cm^3

\\ \bull\tt\longmapsto Density=\dfrac{Mass}{Volume}

\\ \bull\tt\longmapsto Density=\dfrac{18.2}{2.56}

\\ \bull\tt\longmapsto Density=7.1g/cm^3

Metal is not iron

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Answer:

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After completing an experiment to determine gravimetrically the percentage of water in a hydrate, a student reported a value of
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Answer:

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Explanation:

Hi

The percentage of water in the sample is lower than expected.

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4 0
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The normal freezing point of a certain liquid
stepladder [879]

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\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}

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Now put all the given values in this formula, we get

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Therefore, the molal freezing point depression constant of X is 4.12^oC/m

4 0
3 years ago
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