Give the number of covalent bonds in Xenon and phosphorus

What is the approximate wavelength of radio waves

Ulleksa [173]

Answer:

CO32-:

✔ reactant

H2O:

✔ product

CO2:

✔ product

The 2 in front of H+:

✔ coefficient

Explanation:

3 0

2 years ago

What molecule(s) could diffuse across the plasma membrane? question 31 options: disaccharides fe2 tryptophan amino acid ch4

nevsk [136]

The molecule that could diffuse across the plasma membrane is methane (CH4).

<h3>What is diffusion?</h3>

Diffusion is the movement of fluids or substances from regions of high concentration toward regions of lower concentration.

The plasma membrane is the semipermeable membrane that surrounds the cytoplasm of a cell. The semipermeability means that it allows some molecules through but blocks other substances.

The semipermeable plasma membrane readily allows the passage of small hydrophobic and polar molecules.

Therefore, the molecule that could diffuse across the plasma membrane is methane (CH4).

Learn more about semipermeability at: brainly.com/question/1652796

#SPJ1

7 0

1 year ago

26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to

frozen [14]

Answer:

In the final solution, the concentration of sucrose is 0.126 M

Explanation:

Hi there!

The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:

Ci · Vi = Cf · Vf

Where:

Ci = concentration of the original solution

Vi = volume of the solution taken to prepare the more diluted solution.

Cf = concentration of the more diluted solution.

Vf = volume of the more diluted solution.

For the first dillution:

26.6 ml · 2.50 M = 50.0 ml · Cf

Cf = 26.6 ml · 2.50 M / 50.0 ml

Cf = 1.33 M

For the second dilution:

16.0 ml · 1.33 M = 45.0 ml · Cf

Cf = 16.0 ml · 1.33 M / 45.0 ml

Cf = 0.473 M

For the third dilution:

20.0 ml · 0.473 M = 75.0 ml · Cf

Cf = 20.0 ml · 0.473 M / 75.0 ml

Cf = 0.126 M

In the final solution, the concentration of sucrose is 0.126 M

7 0

2 years ago

What is the result of multiplying (2.5 × 1010) × (3.5 × 10-7)? Use the correct number of significant digits.

kow [346]

the result of multiplying (2.5 × 10¹⁰) and (3.5 × 10⁻⁷) is 8.8.10³ (cause the result must have 2 significant number)

<h3><em>Further Explanation</em> </h3>

Significant numbers are numbers obtained from the measurement results of exact numbers and the last number estimated

In scientific notation, all numbers are displayed before the big order is called significant numbers

the scientific notation can be described as:

a, ... x 10ⁿ

a, ... called an important number

10ⁿ is called a big order

Rules for significant numbers in general:

1. all non-zero numbers are significant numbers

2. a zero which is located between two non-zero numbers including a significant number

3. all zeros are located in the final row written behind the decimal point include significant number

4. zero decimal point is not significant number

In the question it is known that (2.5 × 10¹⁰) and (3.5 × 10⁻⁷) both have a significant number in a row 2.5 and 3.5

so that it meets the rule of significant numbers which is multiplication of 2 significant number produces numbers that have the fewest significant numbers, So the multiplication of the two will produce 2 significant number

So that we do the significant number then proceed a big order