Answer:
C. product costs and expensed when the goods are sold
Explanation:
Answer:
146 g
Explanation:
Step 1. Calculate the <em>molar mass</em> of NaNO₃
Na = 22.99
N = 14.01
3O = 3 × 16.00 = 48.00
Total = 85.00 g/mol
Step 2. Calculate the <em>mass</em> of NaNO₃
Mass of NaNO₃ = 1.72 × 85.00/1
Mass of NaNO₃ = 146 g
Answer:
I wouldn’t know I aint never seen two be pretty best friends
Explanation:
C ........................
The problem can solved using the heat equation which is expressed as:
H = mCΔT
where H is the energy absorbed or released, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.
2208 J = 41 g x 4.18 J/g·°C x ( T - 24 °C)
T = 36.88 °C
