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Kazeer [188]
3 years ago
10

How many grams of water are needed to react with 44.9 grams of li2o?

Chemistry
1 answer:
german3 years ago
4 0
The  grams  of  water   needed  to  react  with  44.9  grams  of Li2O  is  calculated as  follows 

write  the  equation  for  reaction
Li2O  +H2O  = 2LiOH

find  the  moles  of  Li2O  =  mass/molar   mass
=  44.9/29.9  =  1.5  moles

by  use  of  reacting  ratio  between   Li2O to  H2O  which  is  1:1  the  moles  of  H2O  is  therefore =  1.5  moles

mass  is  therefore  =  moles  x molar  mass
= 1.5 mol  x 18 g/mol  =  27  grams

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Answer : The specific heat of metal is 0.481J/g^oC.

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

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where,

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m_2 = mass of water = 45.00 g

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T_2 = initial temperature of water = 20.4^oC

Now put all the given values in the above formula, we get

129.00g\times c_1\times (39.6-97.8)^oC=-45.00g\times 4.184J/g^oC\times (39.6-20.4)^oC

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4 years ago
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494.1 kPa

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Where;

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