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Kazeer [188]
3 years ago
10

How many grams of water are needed to react with 44.9 grams of li2o?

Chemistry
1 answer:
german3 years ago
4 0
The  grams  of  water   needed  to  react  with  44.9  grams  of Li2O  is  calculated as  follows 

write  the  equation  for  reaction
Li2O  +H2O  = 2LiOH

find  the  moles  of  Li2O  =  mass/molar   mass
=  44.9/29.9  =  1.5  moles

by  use  of  reacting  ratio  between   Li2O to  H2O  which  is  1:1  the  moles  of  H2O  is  therefore =  1.5  moles

mass  is  therefore  =  moles  x molar  mass
= 1.5 mol  x 18 g/mol  =  27  grams

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Answer:

60 cm³ of water

Explanation:

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Therefore, 60 cm³ of water is needed to dilute the solution.

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Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

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Putting values in above equation, we get:

1.21\times 10^{-4}=\frac{2.303}{t}\log\frac{100}{75}\\\\t=2377.9yrs

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