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QveST [7]
3 years ago
12

A point particle of mass m1 = 2.00 kg is at the origin and a second point particle of mass m2 = 6.00 kg is on the x axis at x =

8.0 m. Find the gravitational field at the following locations.a. x = 2.0m b. x = 12.0 m c. Find the point on the x axis for which g = 0.
Physics
1 answer:
r-ruslan [8.4K]3 years ago
8 0

Answer:

Ok, the gravitational field in the x-axis can be written as:

g(x) = G*∑mₙ/(xₙ - x)

where the field points in the positive x-axis

where mₙ is the mass of the n-th particle, and xₙ is the position of the n-th particle, then, in our case we have:

g(x) = G*(- 2kg/x + 6kg(8m -x))

then; g(2)  = G*( -2kg/2m + 6kg/(8m- 2m)) = G*( -1kg/m + 1kg/m) = 0

g(12) = G*( -(2/12)kg/m  +6/(8 - 12)kg/m) = G* (-2/12 kg/m - 6/4kg/m) = -G*(20/12)kg/m

and we already find that the point where g(x) = 0 is 2

this is the x such:

G*(- 2kg/x + 6kg(8m -x)) = 0

then, the thing inside the parentheses must be zero, now we have:

2kg/x = 6kg(8m -x)

then:

x/2kg = (8/6) m/kg - x/(6kg)

x (1/(2kg) + 1/(6kg)) = (8/6)m/kg

x*(4/(6kg)) = (8/6)m/kg

x = (8/6)*(6/4)m = 2m

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The heat capacity of nickel is 0.444 J/(g · °C). Calculate the amount of heat needed to raise the temperature of 18 g of nickel
azamat

The final speed of the nickel at the given quantity of heat is determined as 202.1  m/s.

<h3>Final speed of the nickel</h3>

Apply the principle of conservation of energy.

Q = mcΔθ

Q = (18)(0.444)(66 - 20)

Q = 367.63 J

Q = K.E = ¹/₂mv²

2K.E = mv²

v = √(2K.E/m)

where;

  • v is the final speed

v = √(2 x 367.63)/(0.018))

v = 202.1 m/s

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5 0
2 years ago
1. A 3.0 kg mass is tied to a rope and swung in a horizontal circle. If the velocity of the mass is 4.0 ms and
saul85 [17]

10.67m/s²

32N

Explanation:

Given parameters:

Mass of the body = 3kg

velocity of the mass = 4m/s

radius of circle = 0.75m

Unknown:

centripetal acceleration = ?

centripetal force = ?

Solution:

The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:

   Centripetal acceleration  = \frac{v^{2} }{r}

   v is the velocity of the body

    r is the radius of the circle

  putting in the parameters:

   Centripetal acceleration = \frac{4^{2} }{0.75}

    Centripetal acceleration = 10.67m/s²

Centripetal force = m  \frac{v^{2} }{r}

          m is the mass

 Centripetal force = mass x centripetal acceleration

                              = 3 x 10.67

                              = 32N

learn more:

Acceleration brainly.com/question/3820012

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4 0
3 years ago
a car company wants to ensure its newest model can stop in 50 m when traveling at 30 m/s (which is about 108 km/h). if we assume
Brut [27]

A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.

<h3>How to calculate deceleration ?</h3>

While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.

We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.

The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.

velocity of car = 30 m/s

car need to stop in 50m

Deceleration a = v^2 –  u^2 / 2s

                          = 0^2 - 50^2 / 2*30

                          = 11.56

Deceleration of the care = 11.56 ms−2

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8 0
1 year ago
The interest rate that the Fed charges banks that borrow money from it is called A. the discount rate. B. the federal rate. C. t
son4ous [18]
The answer is A. the discount rate.
7 0
3 years ago
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A 700 kg car makes a turn going at 30 m/s with radius of
Gnoma [55]

Answer:5250 N

Explanation: ig:iihoop.vince

5 0
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