A point particle of mass m1 = 2.00 kg is at the origin and a second point particle of mass m2 = 6.00 kg is on the x axis at x =
1 answer:
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Answer:
Orbital period of satellite is 5.83 x 10³ s
Explanation:
The orbital period of satellite revolving around Earth is given by the equation :
.....(1)
Here R is radius of Earth, h is height of satellite from the Earth's surface, M is mass of Earth and G is gravitational constant.
In this problem,
Height of satellite, h = 500 km = 500 x 10³ m
Substitute 6378.1 x 10³ m for R, 500 x 10³ m for h, 5.972 x 10²⁴ kg for M and 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻² for G in equation (1).
<em>T</em> = 5.83 x 10³ s
Answer:
the car accelerates in
Explanation:
here's the solution : -
we know,
=》
=》
=》
=》
so, acceleration = 1500 m/s^2
now,
=》
here, a = acceleration, v = final velocity,
u = initial velocity, t = time taken.
So,
=》
=》
=》
=》