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Arturiano [62]
2 years ago
6

a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The

merry-go-round makes a complete revolution once each second. What is the gentleman bug's angular speed?
Physics
1 answer:
forsale [732]2 years ago
6 0
The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)
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Tina drove 3 miles north and 4 miles west to get to her grandmother’s house. Find the distance and displacement.​
TEA [102]

Answer:

distance = 3 + 4 = 7 mi

displacement is √(3² + 4²) = 5 mi

Explanation:

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Select the correct answer.
11111nata11111 [884]

Answer:

Implicit memory

Explanation:

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An object,initially at rest,is subject to an acceleration of 34m/s. How long will it take for that object to travel 3400m?
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3 years ago
Explain how the pressure at the bottom of a container depends on the container shape and the fluid height
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3 0
3 years ago
How do you calculate the braking distance
Anettt [7]

The braking distance is given by s=\frac{-u^2}{2a}

Explanation:

When the driver of a car hits the pedal of the brakes, the car starts decelerating until it stops. Assuming the deceleration is constant, then the motion is a uniformly accelerated motion, so we can use the following suvat equation:

v^2-u^2=2as

where

u is the initial speed of the car

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v = 0

a is the acceleration of the car

s is the distance travelled by the car during the deceleration, so it is the braking distance

Therefore, re-arranging the equation for s, we find an expression for the braking distance:

s=\frac{-u^2}{2a}

Note that the sign of a is negative since the car is decelerating, therefore the final sign of s is positive.

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago
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