Ask question

Ask question

All categories

3 years ago

6

a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The

merry-go-round makes a complete revolution once each second. What is the gentleman bug's angular speed?

1 answer:

forsale [732]3 years ago

6 0

The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)

You might be interested in

You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it de

Elza [17]

The age of the given rock is 700 million years.

The given parameters;

<em>original mass of the rock, = 20 g</em>
<em>mass of the rock remaining after decay, = 10 g</em>
<em>half life of Uranium, </em> $t_{1/2}$ <em> = 700 years</em>

age of the rock ----------------------------- mass remaining

0 $(t_0)$ ------------------------------------------- 20 g

1 half life ( $1 \ t_{1/2}$ ) ------------------------------ 10 g

Age of the rock $= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years$

Thus, the age of the given rock is 700 million years.

Learn more here:brainly.com/question/23774743

3 0

3 years ago

After being struck by a bowling ball, a 1.7 kg bowling pin sliding to the right at 3.8 m/s collides head-on with another 1.7 kg

Alchen [17]

Answer:

3 m/s

Explanation:

Parameters given:

Mass of first bowling pin, m = 1.7 kg

Initial velocity of first bowling pin, u = 3.8 m/s

Final velocity of first bowling pin, v = 0.8 m/s

Mass of second bowling pin, M = 1.7 kg

Initial velocity of second bowling pin, U = 0 m/s

Let the final velocity of the second bowling pin be V

Using the principle of conservation of momentum:

Total initial momentum = Total final momentum

m*u + M*U = m*v + M*V

(1.7 * 3.8) + 0 = (1.7 * 0.8) + (1.7 * V)

6.46 = 1.36 + 1.7V

1.7V = 5.1

V = 5.1/1.7 = 3 m/s

7 0

4 years ago

Student in ms sawyers class built balloon cars the balloon car works this way as the gas in the balloon is released the car move

RUDIKE [14]

Answer:

Third Law of Motion

Explanation:

7 0

3 years ago

Help plssssssssssssssssssss

a_sh-v [17]

Answer:

"humans cannot hear all the same sound frequencies as animals", & "Humans cannot make make all the same sound frequencies as animals" are correct. the other two are incorrect, hope this helps!

3 0

3 years ago

Read 2 more answers

A force of 44 N will stretch a rubber band 88 cm (0.080.08 m). Assuming that Hooke's law applies, how far will aa 11-N forc

Setler79 [48]

Answer:

<em>The rubber band will be stretched 0.02 m.</em>

<em>The work done in stretching is 0.11 J.</em>

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = <em>0.02 m</em>

<em>The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch</em>. This is in line with energy conservation.

potential energy stored = $\frac{1}{2}ke^{2}$

==> $\frac{1}{2}* 550* 0.02^{2}$ = <em>0.11 J</em>

3 0

3 years ago