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Arturiano [62]
3 years ago
6

a ladybug sits at the outer edge of a merry-go-round and a gentleman bug sits halfway between her and the axis of rotation. The

merry-go-round makes a complete revolution once each second. What is the gentleman bug's angular speed?
Physics
1 answer:
forsale [732]3 years ago
6 0
The gentleman bug's angular speed is the same as the ladybug's (1 rev/s)
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For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

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mass, M = 63.5 g/mol

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Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

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J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

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V_d=\frac{J}{ne}

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She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

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The focal length is a measure of how strongly the system converges or diverges light.

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