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WITCHER [35]
2 years ago
13

If pea plants with the genotypes RR and rr cross, what genotype will their offspring all have?

Chemistry
2 answers:
Aliun [14]2 years ago
6 0
I think it’ll be Rr
Ann [662]2 years ago
5 0
The genotype of the f1 generation will be 100% heterozygous Rr
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Help me now plssssssss i will give brainliest!!!!!!!!!!!!!!!!!!!!!!!
Blababa [14]
Products are copper+ aluminium chloride
reactants are aluminium+copper chloride
5 0
3 years ago
Complete combustion of 5.90 g of a hydrocarbon produced 18.8 g of CO2 and 6.75 g of H2O.
Inessa05 [86]
First we have to find moles of C:
Molar mass of CO2:
12*1+16*2 = 44g/mol
(18.8 g CO2) / (44.00964 g CO2/mol) x (1 mol C/ 1 mol CO2) =0.427 mol C 
Molar mass of H2O:
2*1+16 = 18g/mol
As there is 2 moles of H in H2O,
So,

<span>(6.75 g H2O) / (18.01532 g H2O/mol) x (2 mol H / 1 mol H2O) = 0.74mol H </span>

<span>Divide both number of moles by the smaller number of moles: </span>
<span>As Smaaler no moles is 0.427:
So,
Dividing both number os moles by 0.427 :
(0.427 mol C) / 0.427 = 1.000 </span>
<span>(0.74 mol H) / 0.427 = 1.733 </span>

<span>To achieve integer coefficients, multiply by 2, then round to the nearest whole numbers to find the empirical formula: 
C = 1 * 2 = 2
H = 1.733 * 2 =3.466
So , the empirical formula is C2H3</span>
4 0
3 years ago
Read 2 more answers
Why must a new flu vaccine be manufactured annually?
mafiozo [28]

Answer:

D or A

<em>But I do know...</em>

It's because new strains of the virus are constantly appearing and evolving, so the vaccine must change along with them.

7 0
1 year ago
an, 13 Students set up two environments see which one best supports growth of hibiscus flowers. One environment is created as a
Assoli18 [71]
B. The Enviroment. The Soil and Humidity are differant. They both have high tematures, they use the same flowers in both, Hibiscus. The tropical environent should help the Hiviscus grow better.
8 0
3 years ago
A flask has a mass of 78.23g when empty and 593.63g when filled with water.When the same flask is filled with concentrateds ulfu
butalik [34]

Answer:

Density of concentrated H2SO4 = 1.99g/cm^3 = 1991.79Kg/m^3

Explanation:

mass of empty flask = 78.23g mass of flask filled when with water = 593.63g.

mass of flask filled when with concentrateds sulfuric acid, H2SO4 = 1026.57g

Mass of water = (mass of flask filled when with water) -

(mass of empty flask) = 593.63g - 78.23g = 515.4g

Volume of flask = volume of water = volume of concentrateds sulfuric acid, H2SO4 =

(mass of water)/ density of water) = 515.4g/1.00g/cm^3 = 515.4cm^3

The density of concentrated sulfuric acid is given by

Density of concentrated H2SO4 = (mass of H2SO4) ÷ (volume of H2SO4) = 1026.57g/515.4cm^3 = 1.99g/cm^3 = 1991.79Kg/m^3

7 0
2 years ago
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