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3 years ago

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An atom has the following electron configuration 1s2s2sp63s23p64s2 How many valance electrons does this atom have?

1 answer:

JulijaS [17]3 years ago

6 0

Answer:

The electron configuration for this atom is Calcium, which has 2 valence electrons.

Explanation:

Following the periodic table and with the electron configuration, you will end up with calcium, which has 2 valence electrons. (Always follow the electron configuration from left to right! It begins at hydrogen, then to helium... and so on.)

1s2 -> He....

2s2 -> Be....

2p6 -> Ne...

3s2 -> Mg...

3p6 -> Ar...

4s2 -> Ca.

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What is the name of this compound?

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3 years ago

The work done to compress a gas is 83.0 J. As a result, 27.0 J of heat is given off to the surroundings. Calculate the change in

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Answer:

ΔU° = 56.0 J

Explanation:

Step 1: Given data

Work done to compress the gas (w): 83.0 J (When work is done on the gas, w is positive).

Heat given off to the surroundings (q): -27.0 J (When heat is released to the surroundings, q is negative)

Step 2: Calculate the change in the internal energy of the gas (ΔU°)

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3 years ago

Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

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<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399

<u>Explanation:</u>

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

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3 years ago