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Anestetic [448]

3 years ago

12

Answer the three questions below that pertain to atomic orbitals. Part A: No two electrons can have the same set of quantum numb

ers. This idea is known as what? There is no name for this idea. the Hawking Uniqueness Hypothesis the Pauli Exclusion Principle the Feynman Singularity Statement the deBroglie Wavelength Caveat

1 answer:

zimovet [89]3 years ago

8 0

Answer:

Pauli exclusion principle

Explanation:

No two fermions can have the same set of quantum numbers is called the Pauli exclusion principle. And a electron is a fermion.

There are four basic quantum numbers

Principle quantum number n

the angular momentum quantum number l

magnetic quantum number m_l

and electron spin quantum number m_s

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The needle in the following diagram rotates around a fixed point in the middle. Based on the information given, what way will th

Ronch [10]

Answer:

nods 40th anniversary rid off e 49en9 snns

3 0

3 years ago

Put the following words in order from smallest to largest: atoms, matter, elements

WINSTONCH [101]

Answer:

Matter, atoms, elements.

Explanation:

Matter is just a name for anything that has mass and takes up space. Therefore, atoms are larger than matter. Atoms are the smallest bits of an element that <em>are</em><em> </em><em>still</em><em> </em><em>that</em><em> </em><em>element</em>, so, elements would be bigger than the atoms that come together to create them!

Hope this helps!

6 0

2 years ago

Phil is riding a scooter and pushes off the ground with his foot. this causes him to accelerate at 12 m /s. Phil weighs 600 N. h

Dvinal [7]

Answer:

734.16 kg m/ $s^{2}$

Explanation:

The problem is asking for the Force of pushing off the ground.

The formula of Force is: F = mass x acceleration

Given = <em>Mass</em>: 600 newtons (N)

<em>Acceleration</em>: 12 m/ $s^{2}$

We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>

Let x be the<em> mass in newtons</em>.

Let's convert: $\frac{1 kg}{9.80665 N}$ x $\frac{x}{600 N}$ = $\frac{600}{9.80665}$ = 61.18 kg

Phil's weight is 61.18 kg

Let's go back to finding the force.

F = m x a

F = 61.18 kg x 12 m/ $s^{2}$

F = 734.16 kg m/ $s^{2}$

7 0

2 years ago

Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia

sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

$s_A = -6 + 9t$

$s_B = 5 - 8t$

When A an B meets, they are at the same position and at the same time. So

$s_A = s_B$

$-6 +9t = 5 - 8t$

$17t = 5 + 6 = 11$

$t = 11/17 = 0.647 s$

$s_A = -6 + 9*0.647 = -0.176 m$

So where they meet is 0.176m from the flagpole, westward.

5 0

3 years ago

Can someone please help me

Tamiku [17]

<em>F</em> = 153 N

$\theta = 11.3°$

Explanation:

Let us define first our directional convention. Anything pointing up or to the right is considered positive and anything pointing down or to the left is considered negative. Now let's look at the components $F_{x}$ and $F_{y}$ :

$F_{x}$ = 350 N - 200 N = 150 N

$F_{y}$ = 180 N - 150 N = 30 N

The magnitude of the resultant force <em>F</em> is given by

$F = \sqrt{F_{x}^{2}+F_{y}^{2}}$

$\:\:\:\:\:\:= \sqrt{(150\:N)^{2}+(30\:N)^{2}}$

$\:\:\:\:\:\:=153\:N$

To find the direction $\theta$ , we use

$\tan \theta = \dfrac{F_{y}}{F_{x}}=\dfrac{30\:N}{150\:N}=0.2$

or

$\theta = \tan^{-1}(0.2) = 11.3°$

4 0

3 years ago