This is called an organ. Examples of organs are: your heart, brain, lungs, liver, stomach etc.
Answer:
The heat exchanger is 29.26 kJ/s.
The exit temperature of geothermal water is 117.37°C.
Explanation:
Given that,
Specific heat 
Initial temperature = 25°C
Final temperature = 60°C
Specific heat by geothermal 
Temperature = 140°C
Mass flow rate = 0.3 kg/s
We need to calculate the rate of heat transfer in heat exchange
Using formula of rate of heat transfer in heat exchanger

Put the value into the formula


We need to calculate the exit temperature of geothermal water
Heat transferred to feed water= Heat transferred by geothermal water



Hence, The rate of heat exchanger is 29.26 kJ/s.
The exit temperature of geothermal water is 117.37°C.
Answer: the air above a wildfire
Explanation:
First part of question is: The diagram shows currents that form as water is heated.
When water is being heated from below, convection currents are used. This happens when the molecules at the bottom are heated thus giving them energy and enabling them rise to the surface. The colder water at the surface will therefore sink to the bottom where is is heated making it rise as well and the process is repeated.
When a wildfire is ignited, the concept is the same. The air above the wildfire is the water in this scenario. It is heated at the bottom and rises thereby forcing the air above to come down and be heated as well. Both situations uses convectional currents.
The first law of thermodynamics states that:

where

is the variation of internal energy of the system
Q is the heat absorbed by the system
L is the work done by the system on the surrounding.
In this problem, the system absorbs 15 J of heat, so Q=+15 J (with positive sign, since it is heat absorbed by the system) while the work done by the system is L=+7 J (with positive sign, since it is work done by the system), so the variation of internal energy is
Answer:
F
T
F
T
T
Explanation:
Thanks for this oppurtunity