In physics, weight is a measure of the force exerted by gravity on a mass.
You probably know that you weigh less on the Moon than on Earth. For instance, if you weigh 100. pounds on Earth, you will weigh 16.6 pounds on the Moon. But, if your mass on Earth is 100 kg, your mass on the Moon is... also 100 kg. Because the amount of matter you have does not change from the Earth to the Moon, but the gravitational force on the Earth is stronger than on the Moon, so you weigh more on Earth.
You can think of gravity pulling a mass toward the center of an object like the Earth. It pulls a lot harder for more massive objects like the Earth than for the Moon. That's why there's a difference in weight.
As a caveat, adding energy or mass to an object will affect its mass. Additionally, general relativity informs us that when something as traveling very near the speed of light, the whole idea of mass equivalency is not exactly true...
Answer:
-100000 N.
Explanation:
Force: This can be defined as the product of the mass of a body and it's acceleration. The S.I unit of Force is Newton(N). The Formula of force is given as,
F = ma ........................... Equation 1
Where F = Average force exerted on the car, m = mass of the car, acceleration of the car, a = acceleration of the car.
a = (v-u)/t..................... Equation 2
Where v = Final velocity, u = Initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............. Equation 3
Given: m = 1500 kg, u = 20 m/s, v = 0 m/s (brought to rest), t = 0.3 s.
Substitute into equation 3
F = 1500(0-20)/0.3
F = 1500(-20)/0.3
F = -100000 N.
Note: The negative sign is due to the fact that the force exerted on the car by the pole is equal and opposite the force of the car.
Answer:
0.6 Ω
Explanation:
As shown in the diagram below,
Since the resistance and the ammeter are connected in series,
(i) The same amount of current flows through them.
(ii) The sum of their individual individual voltage is equal to the total voltage of the circuit.
Applying ohm's law,
V = IR................ Equation 1
Where V = Voltage across the ammeter, I = current flowing through the ammeter, R = resistance of the ammeter.
make R the subject of the equation
R = V/I............... Equation 2
Given: V = 1.2-0.9 = 0.3 V, I = 0.5 A.
Substitute into equation 2
R = 0.3/0.5
R = 0.6 Ω
F = ma so u can plug in the given numbers and solve:
F = (2)(3)
