A diver who has a mass of 68 kg climbs to a diving platform that is 7.5 m above the surface of a pool. How much gravitational po
2 answers:
Answer: 4,998 J
Explanation:
The gravitational potential energy of an object is given by
where
m is the mass of the object
g is the gravitational acceleration
h is the heigth of the object with respect to a reference point
In this problem, m=68 kg, g=9.8 m/s^2, and h=7.5 m is the heigth of the diver with respect to the surface of the pool. Therefore, the gravitational potential energy of the diver with respect to the surface of the pool is
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Answer:
91.48N/m
Explanation:
In a spring-mass system undergoing a simple harmonic motion, the inverse of the frequency f, of oscillation is proportional to the square root of the mass m, and inversely proportional to the square root of the spring constant, k. This can be expressed mathematically as follows;
=
-----------(i)
From the question;
f = 3.26 Hz
m = 0.218kg
Substitute these values into equation (i) as follows;
=
[<em>Square both sides</em>]
()² = (
)²(
)
() =
²(
) [<em>Take </em>
<em> to be 3.142</em>]
() =
²(
)
() =
(
)
() = (
) [<em>Switch sides</em>]
() = (
) [<em>Re-arrange</em>]
() = (
) [<em>Cross-multiply</em>]
k = 8.608 x 10.6276
k = 91.48N/m
Therefore, the spring constant of the spring is 91.48N/m