Question

17

Answer 1

Answer:

Heat energy required (Q) = 70,537.5 J

Explanation:

Given:

Mass of water (m) = 225 grams

Initial temperature of water =  25.0°C

Final temperature of water = 100.0°C

Specific heat of water (c) = 4.18 J/g

Find:

Heat energy required (Q)

Computation:

Change in temperature Δt = Final temperature of water - Initial temperature of water

Change in temperature Δt = 100 - 25

Change in temperature Δt = 75°C

Using Heat energy formula

Q = (m)(c)(Δt)

Heat energy required (Q) = (225)(4.18)(75)

Heat energy required (Q) = 70,537.5 J