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2 years ago

17

Physics

1 answer:

ivann1987 [24]2 years ago

3 0

Answer:

Heat energy required (Q) = 70,537.5 J

Explanation:

Given:

Mass of water (m) = 225 grams

Initial temperature of water = 25.0°C

Final temperature of water = 100.0°C

Specific heat of water (c) = 4.18 J/g

Find:

Heat energy required (Q)

Computation:

Change in temperature Δt = Final temperature of water - Initial temperature of water

Change in temperature Δt = 100 - 25

Change in temperature Δt = 75°C

Using Heat energy formula

Q = (m)(c)(Δt)

Heat energy required (Q) = (225)(4.18)(75)

Heat energy required (Q) = 70,537.5 J

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Llana [10]

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2 years ago

Read 2 more answers

A 2498 kg car is moving at 17.1 m/s slams on its brakes and slows to 2.6 m/s. What is the magnitude (absolute value) of the impu

bija089 [108]

Answer:

Explanation:

<u>Impulse-Momentum Theorem</u>

These two magnitudes are related in the following way. Suppose an object is moving at a certain speed $v_1$ and changes it to $v_2$ . The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

$p=mv$

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$p_1=mv_1,\ p_2=mv_2$

The change of momentum is

$\Delta p=p_2-p_1=m(v_2-v_1)$

It is numerically equal to the Impulse J

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$J=m(v_2-v_1)$

We are given

$m=2498\ kg,\ v_1=17.1\ m/s,\ v_2=2.6\ m/s$

The impulse the car experiences during that time is

$J=2498(2.6-17.1)=2498(-14.5)$

J=-36221 Kg.m/s

The magnitude of J is

J=36221 Kg.m/s

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