Answer:
Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to speed up (gain momentum) and the other object to slow down (lose momentum).
Answer:
<em>126.01 rad/s^2</em>
<em></em>
Explanation:
since it starts from rest, initial angular speed ω' = 0 rad/s
angular speed N = 477 rev/min
angular speed in rad/s ω =
=
= 49.95 rad/s
angular displacement ∅ = 1.5758 rev
angular displacement in rad/s =
= 2 x 3.142 x 1.5758 = 9.9 rad
angular acceleration
= ?
using the equation of angular motion
ω^2 = ω'^2 + 2
∅
imputing values, we have

2495 = 19.8
= 2495/19.8 = <em>126.01 rad/s^2</em>
Answer:183.94 N
Explanation:
Given
Time Period 
mass of child 
Radius 
Velocity 


Now Centripetal Force will be Balanced by Frictional Force
Centripetal Force 


therefore Friction Force is 183.94 N
<span>They occur when the Earth, the Sun, and the Moon are in a line. </span>
Answer:
It is easier to stop the bicycle moving at a lower velocity because it will require a <em>smaller force</em> to stop it when compared to a bicycle with a higher velocity that needs a<em> bigger force.</em>
Explanation:
The question above is related to "Newton's Law of Motion." According to the <em>Third Law of Motion</em>, whenever an object exerts a force on another object <em>(action force)</em>, an equal force is exerted against it. This force is of the same magnitude but opposite direction.
When it comes to moving bicycles, the force that stops their movement is called "friction." Applying the law of motion, the higher the speed, the higher the force<em> </em>that is needed to stop it while the lower the speed, the lower the force<em> </em>that is needed to stop it.