Explanation:
It is given that,
Initial speed of sprinter, u = 0
Final speed of sprinter, v = 10 m/s
Time taken, t = 1.28 s
a. We need to find the acceleration of sprinter. It can be calculated using first equation of motion as :
b. Final speed of the sprinter, v = 36 km/h
Time, t = 0.000355 h
Acceleration, 
Hence, this is the required solution.
Kinetic energy of golf club = 65J,
kinetic energy supplied to golf ball = 20% of 65 = 0.2 * 65 = 13J,
kinetic energy of ball = [mass * Velocity²]/2,
mass = 46gm = 0.046Kg,
[0.046 * V²]/2 = 13, or 0.046 *V² = 26,
V² = 26/0.046 = 565.22,
V = 23.77 m/sec = initial velocity of golf ball after hitting.
Answer:
The answer to your question is: a = 1.99 m/s²
Explanation:
Data
mass = 20 kg
angle = 56°
Force = 71 N
horizontal acceleration = ?
Process
Find the horizontal force
cos Ф = adjacent side / hypotenuse
adjacent side = hypotenuse x cosФ
adjacent side = 71 x cos 56
a.s. = 39.70 N
Newton's second law
F = ma
a = F/m
a = 39.7 / 20
a = 1.99 m/s²
I believe it would be x because you are trying to find the width of the wave but i could be wrong
Answer:
24.4 m
Explanation:
first we have to calculate how long the cat will be in the air, in vertical direction this is free fall from 4m (poor cat, hope he survived) with acceleration of g=9.81 m/s^2
time = sqrt ( 2 * height / g)
time = sqrt (2 * 4 / 9.81)
time = 0,903 s
then we know his horizontal flight was 22 m long, so ve can calculate verical speed
speed = length / time
speed = 22 m / 0,903 s
speed = 24.363 m
as you are asked to give 3 significant numbers answer is 24,4 m
