Answer:By definition, perpendicular line are two lines that intersect at right angles. In other words, the angle made by two lines should be 90°. Therefore, the use of distance formula does not help because it only tells you if the sides are equal. It does not tell you about the intercepted angle.
A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.
Therefore, the answer is: Find the slopes and show that their product is -1.
hope it help
Answer:
A
Step-by-step explanation:
Compare the images to 90°, which is right angle, and forms an L. A is just past 90°, B is past 270°, and C is less than 90°.
Answer:
x = 5, y = -1/2
Step-by-step explanation:
3.5x - 5y = 20
3x + 4y = 13 multiply by 1.25 so the y's match up (you could match x's too)
3.75x + 5y = 16.25
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3.5x - 5y = 20
3.75x +5y = 16.25
7.25x + 0y = 36.25 you can add or subtract here (on this equation you add)
7.25x=36.25
x=5 So now we have x=5 and to find y we can just plug in x into one of the equations
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3(5) + 4y = 13
15 + 4y = 13
4y = -2
y = -1/2
x = 5, y = -1/2
Then you can plug in both to check your answers.
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
