Solution :
Given :
External diameter of the hemispherical shell, D = 500 mm
Thickness, t = 20 mm
Internal diameter, d = D - 2t
= 500 - 2(20)
= 460 mm
So, internal radius, r = 230 mm
= 0.23 m
Density of molten metal, ρ = 
= 
The height of pouring cavity above parting surface is h = 300 mm
= 0.3 m
So, the metallostatic thrust on the upper mold at the end of casting is :
Area, A 
= 7043.42 N
Answer:
When the brakes are applied the in the typical double transverse wishbone front suspension, it "drives" the car ground due to the setting of the link-type system pivot points on the lower wishbone are have parallel alignment to the road
Explanation:
In order to minimize the car's reaction to the application of the brakes, the front and rear pivot are arranged with the lower wishbone's rear pivot made to be higher than the front pivot as such the inclined wishbone torque results in an opposing vertical force to the transferred extra weight from the back due to breaking.
Answer:
A working with machinery be a common type of caught-in and caught-between hazard is described below in complete detail.
Explanation:
“Caught in-between” accidents kill mechanics in a variety of techniques. These incorporate cave-ins and other hazards of tunneling activity; body parts extracted into unconscious machinery; reaching within the swing range of cranes and other installation material; caught between machine & fixed objects.
Answer:
The temperature T= 648.07k
Explanation:
T1=input temperature of the first heat engine =1400k
T=output temperature of the first heat engine and input temperature of the second heat engine= unknown
T3=output temperature of the second heat engine=300k
but carnot efficiency of heat engine =
where Th =temperature at which the heat enters the engine
Tl is the temperature of the environment
since both engines have the same thermal capacities <em>
</em> therefore 
We have now that
multiplying through by T
multiplying through by 300
-
The temperature T= 648.07k
Answer:
230.51 m
Explanation:
Pb = 695 mmHg
Pt = 675 mmHg
Pb - Pt = 20 mmHg
Calculate dP:
dP = p * g * H = (13600)*(9.81)*(20/1000) = 2668.320 Pa
Calculate Height of building as dP is same for any medium of liquid
dP = p*g*H = 2668.320
H = 2668.32 / (1.18 * 9.81) = 230.51 m
