If noise levels are high enough that you have to raise
1 answer:
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Answer:
There are 2 expected readings greater than 2.70 V
Solution:
As per the question:
Total no. of readings, n = 60 V
Mean of the voltage,
standard deviation,
Now, to find the no. of readings greater than 2.70 V, we find:
The probability of the readings less than 2.70 V, :
Now, from the Probability table of standard normal distribution:
Now,
Now, for the expected no. of readings greater than 2.70 V:
No. of readings expected to be greater than 2.70 V =
No. of readings expected to be greater than 2.70 V = ≈ 2