Well you could always do what Hispanics do and repeat the question 2-3 times while yelling till they finally answer
Answer:
Explanation:
Sum of the side slope = 2 + 1 = 3
Length of first slope = 2/3 X 3.6 = 2 X 1.2 = 2.4m
Lenght of second slope = 1/3 X 3.6 = 1.2m
Area of the trapezoidal channel = (2.4 + 1.2)/2 X 3.6 = 1.8 X 3.6 = 6.48m²
Alternate dept = 50m³/6.48m²= 7.716m
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness 
= 92 Mpa√m
yield strength σ
= 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length 
= 1/π( / Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection
Given Information:
Output power required = Pout = 2.80 MW
Efficiency = η = 30%
Intensity = I = 1180 W/m²
Required Information:
Effective area = A = ?
Answer:
Effective area = A = 7.907x10³ m²
Step-by-step explanation:
A community plans to build a facility to convert solar power into electrical power and this facility has an efficiency of 30%
As we know efficiency is given by
η = Pout/Pin
Where Pout is the output power and Pin is the input power.
Pin = Pout/η
Pin = 2.80x10⁶/0.30
Pin = 9.33x10⁶ W
The effective area of a perfectly absorbing surface used in such an installation can be found using
A = Pin/I
Where I is the in Intensity of the sunlight in W/m²
A = 9.33x10⁶/1180
A = 7.907x10³ m²
Therefore, the effective area of the absorbing surface would be 7.907x10³ m².
True .the chlorofluorocarbons also known as CFC’s also contribute on depleting the ozone layer
